I have to insert documents in MongoDB in a left-shift manner ie if the collection contains 60 documents, I am removing the 1st document and I want to insert the new document at the rear of the database. But when I am inserting the 61st element and so forth, the documents are being inserted in random positions. Is there any way I can insert the documents in the order that I specified above? Or do I have to do this processing when I am retrieving the values from the database? If yes then how? The data format is :
data = {"time":"10:14:23", #timestamp
"stats":[<list of dictionaries>]
}
The code I am using is
from pymongo import MongoClient
db = MongoClient().test
db.timestamp.delete_one({"_id":db.timestamp.find()[0]["_id"]})
db.timestamp.insert_one(new_data)
the timestamp is the name of the collection.
Edit: Changed the code. Is there any better way?
from pymongo.operations import InsertOne,DeleteOne
def save(collection,data,cap=60):
if collection.count() == cap:
top_doc_time= min(doc['time'] for doc in collection.find())
collection.delete_one({'time':top_doc_time['_time']})
collection.insert_one(data)
A bulk write operation guarantees query ordering by default . This means that the queries are executed sequentially.
from pymongo.operations import DeleteOne, InsertOne
def left_shift_insert(collection, doc, cap=60):
ops = []
variance = max((collection.count() + 1) - cap, 0)
delete_ops = [DeleteOne({})] * variance
ops.extend(delete_ops)
ops.append(InsertOne(doc))
return collection.bulk_write(ops)
left_shift_insert(db.timestamp, new_data)
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