How to schedule a cron job every 4 hour 48 minutes?

Question

Do I have to write 5 cronjobs for this?

The only other thing I have in mind is */48 */4 *** , but I don't think that works

Answer 1

I don't think it is possible only with crontab but you can use a script. copy and paste the following on a terminal; obviosuly you need to change the first row by replacing /home/hf/ with an existing folder,
eventually replace myloop.sh with a more meaningful name (optional) and replacing /path/to/script.sh with the script or command you need to launch

export myhome=/home/hf/ ; export loopbat=myloop.sh ; export scripttorun=/path/to/script.sh

echo "COUNTER=0" > ${myhome}${loopbat}
echo "while [  \$COUNTER -lt 5 ]; do" >> ${myhome}${loopbat}
echo "   echo The counter is \$COUNTER" >> ${myhome}${loopbat}
echo "   /bin/bash $scripttorun" >> ${myhome}${loopbat}
echo "   let COUNTER=COUNTER+1" >> ${myhome}${loopbat}
echo "   sleep 17280" >> ${myhome}${loopbat}
echo "done" >> ${myhome}${loopbat}

then call the loop script from crontab once per day

00 00 * * * /home/hf/myscript.sh

Answer 2

You can use like that 48 */4 * * * echo "bla bla bla" >> /homu/x/Desktop/example.txt >/dev/null 2>&1 in crontab file or use command of crontab and you can use MAN for understand crontab. If you wont do, I can help you as spesifical. For crontab this site help what you want

Answer 3

You were close in your attempt. Try

48 */4 * * *