Here is my table structure:
// mytable
+----+---------+
| id | related |
+----+---------+
| 1 | NULL |
| 2 | 1 |
+----+---------+
Now I need to select the row that has id = 1
and all rows that have related = 1
. Here is my query:
select m1.*
from mytable m1
left join mytable m2 on m1.id = m2.related
where m1.id = 1
But it returns just the first row. What's wrong?
You can do:
select t.*
from mytable t
where 1 in (id, related);
No self-join is needed.
EDIT:
If you want performance, then write the query as:
select t.*
from mytable t
where id = 1
union all
select t.*
from mytable t
where related = 1;
And define two indexes on mytable(id)
and mytable(related)
.
If I understood correctly you are looking for this:
select m1.*
from mytable m1 where m1.id = 1 or m1.related = 1
You need to use inner join.
select m1.*
from mytable m1
inner join mytable m2 on m1.id = m2.related
where m1.id = 1
You can try UNION ALL or if you don't want duplicates use UNION
select * from mytable m1 where m1.id = 1
UNION
select * from mytable m2 where m2.related = 1
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