I'm trying to implement factory method pattern in my QT project following this example: https://www.codeproject.com/Articles/363338/Factory-Pattern-in-Cplusplus
#include <QCoreApplication>
#include <QDebug>
class IAnimal
{
public:
virtual int GetNumberOfLegs() const = 0;
virtual void Speak() = 0;
virtual void Free() = 0;
};
typedef IAnimal* (__stdcall *CreateAnimalFn)(void);
// IAnimal implementations
class Cat : public IAnimal
{
public:
int GetNumberOfLegs() const { return 4; }
void Speak() { qDebug() << "Meow" << endl; }
void Free() { delete this; }
static IAnimal * __stdcall Create() { return new Cat(); }
};
class Dog : public IAnimal
{
public:
int GetNumberOfLegs() const { return 4; }
void Speak() { qDebug() << "Woof" << endl; }
void Free() { delete this; }
static IAnimal * __stdcall Create() { return new Dog(); }
};
Factory class:
// Factory for creating instances of IAnimal
class AnimalFactory
{
private:
AnimalFactory();
AnimalFactory(const AnimalFactory &) { }
AnimalFactory &operator=(const AnimalFactory &) { return *this; }
typedef QMap<QString,CreateAnimalFn> FactoryMap;
FactoryMap m_FactoryMap;
public:
~AnimalFactory() { m_FactoryMap.clear(); }
static AnimalFactory *Get()
{
static AnimalFactory instance;
return &instance;
}
void Register(const QString &animalName, CreateAnimalFn pfnCreate);
IAnimal *CreateAnimal(const QString &animalName);
};
AnimalFactory::AnimalFactory()
{
Register("Cat", &Cat::Create);
Register("Dog", &Dog::Create);
}
void AnimalFactory::Register(const QString &animalName, CreateAnimalFn pfnCreate)
{
m_FactoryMap[animalName] = pfnCreate;
}
IAnimal *AnimalFactory::CreateAnimal(const QString &animalName)
{
FactoryMap::iterator it = m_FactoryMap.find(animalName);
if( it != m_FactoryMap.end() )
return it.value();
return NULL;
}
However I am encountering such an error:
cannot convert 'IAnimal* (__attribute__((__stdcall__)) *)()' to 'IAnimal*' in return
return it.value();
Only existing anwser ( Insert function pointer into QMap (Qt) ) suggests making Create() functions static which doesn't seem to help.
I will be very grateful for any piece of advice.
That's a little bit complicated. You're writing C++, so you shouldn't be copying Java. C++ is way more expressive here.
Create
/ Free
methods - the compiler can generate them for you, automatically. override
, including the destructor, but not virtual
as that'd violate DRY. #include <QtCore>
class IAnimal {
public:
virtual int GetNumberOfLegs() const = 0;
virtual QString Speaks() = 0;
virtual ~IAnimal() {}
};
class Cat : public IAnimal {
public:
int GetNumberOfLegs() const override { return 4; }
QString Speaks() override { return QStringLiteral("Meow"); }
static auto className() { return "Cat"; }
};
class Dog : public IAnimal {
public:
int GetNumberOfLegs() const override { return 4; }
QString Speaks() override { return QStringLiteral("Woof"); }
static auto className() { return "Dog"; }
};
Now we can have a generic factory. Note that all sane C++ container types manage their data. You don't need to explicitly clear them on destruction. We're leveraging C++11. The Register
method will only accept types that derive from Interface
, and that method automatically generates a construction function using the lambda expression.
The lifetime of the instance should be controlled explicitly by instantiating it in main()
.
#include <type_traits>
#include <typeindex>
#include <map>
template <class Interface> class Factory {
template <class C, class T = void> struct enable_if_I :
std::enable_if<std::is_base_of<Interface, C>::value, T> {};
using create_fn = Interface* (*)();
std::map<QByteArray, create_fn, std::less<>> m_creators;
std::map<std::type_index, QByteArray> m_names;
static Factory *&instance_ref() { // assume no inline static yet
static Factory *m_instance;
return m_instance;
}
Factory(const Factory &) = delete;
Factory &operator=(const Factory &) = delete;
public:
Factory() {
Q_ASSERT(!instance());
instance_ref() = this;
}
virtual ~Factory() { instance_ref() = {}; }
In general, registration requires the type and name of the derived class. This presupposes nothing about whether the class has a className()
member. The factory stores both the factory function and the name. This allows name look up without having className
as a virtual method of the interface.
template <class T> typename enable_if_I<T>::type Register(const QByteArray &name) {
m_creators[name] = +[]()->Interface* { return new T(); };
m_names[{typeid(T)}] = name;
}
When class names are known, we can leverage them to register one or more classes, given just their types.
template <class T1> typename enable_if_I<T1>::type Register() {
this->Register<T1>(T1::className());
}
template <class T1, class T2, class...T> typename enable_if_I<T1>::type Register() {
this->Register<T1>(T1::className());
this->Register<T2, T...>();
}
The instance creation methods are optimized not to copy the name given, no matter the format. This is why we use the std::map<K, V, std::less<>>
map with a transparent comparator. QByteArray
provides operator<
that takes various types on the right-hand side, and to exploit this, the type of the key (here: name) must reach the comparator.
template <typename T> static Interface *CreateA(T &&t) {
return instance() ? instance()->Create(std::forward<T>(t)) : nullptr;
}
Interface *Create(QLatin1String name) const { return Create(name.data()); }
template <typename T> Interface *Create(T &&name) const;
static const QByteArray &NameOfA(const Interface * obj);
const QByteArray &NameOf(const Interface *) const;
static Factory *instance() { return instance_ref(); }
};
template <class Interface>
template <typename T> Interface *Factory<Interface>::Create(T &&name) const {
auto it = m_creators.find(name);
return (it != m_creators.end()) ? it->second() : nullptr;
}
namespace detail {
const QByteArray & null() { static const QByteArray n; return n; }
}
template <class Interface>
const QByteArray &Factory<Interface>::NameOfA(const Interface *obj) {
return instance() ? instance()->NameOf(obj) : detail::null();
}
template <class Interface>
const QByteArray &Factory<Interface>::NameOf(const Interface *obj) const {
auto it = m_names.find(typeid(*obj));
return (it != m_names.end()) ? it->second : detail::null();
}
The generic factory takes the interface and concrete types and registers them all in the constructor. This makes building the factories simple.
template <class Interface, class ...Types>
class GenericFactory : public Factory<Interface> {
public:
GenericFactory() {
this->template Register<Types...>();
}
};
using AnimalFactory = GenericFactory<IAnimal, Cat, Dog>;
Example of use, with asserts to indicate desired behavior. Note that to destroy the objects, one merely has to delete
their instance. The compiler will generate the calls.
int main() {
Q_ASSERT(!AnimalFactory::instance());
{
AnimalFactory animals;
Q_ASSERT(AnimalFactory::instance());
auto *dog1 = AnimalFactory::CreateA("Dog");
Q_ASSERT(dynamic_cast<Dog*>(dog1));
Q_ASSERT(AnimalFactory::NameOfA(dog1) == Dog::className());
Q_ASSERT(dog1->Speaks() == QStringLiteral("Woof"));
auto *dog2 = AnimalFactory::CreateA(QLatin1String("Dog"));
Q_ASSERT(dynamic_cast<Dog*>(dog2));
auto *cat = AnimalFactory::CreateA("Cat");
Q_ASSERT(dynamic_cast<Cat*>(cat));
Q_ASSERT(cat->Speaks() == QStringLiteral("Meow"));
Q_ASSERT(AnimalFactory::NameOfA(cat) == Cat::className());
delete cat;
delete dog2;
delete dog1;
}
Q_ASSERT(!AnimalFactory::instance());
}
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