a <- 1:6;
b <- seq(0.2,8,length.out = 6)
set.seed(1)
d <- runif(6, 0, 1)
e <- rnorm(6, 0, 1)
How do I get the following result: three dimensional array, dim = c(2, 2, 6)
, formed by 6 matrix. The i-th matrix is composed by a[i], b[i], d[i], e[i].
Here is a method using rbind
. This works because R stores matrices by column, so that we can use rbind
to store values of corresponding values of a, b, d, and e together prior to storing in the array.
myArray <- array(rbind(a, b, d, e), c(2, 2, 6))
The first two Z values are
myArray[,,1:2]
, , 1
[,1] [,2]
[1,] 1.0 0.2655087
[2,] 0.2 1.5952808
, , 2
[,1] [,2]
[1,] 2.00 0.3721239
[2,] 1.76 0.3295078
array_test <- array(,c(2, 2, 6))
for(i in 1:6){
array_test[,,i] <- matrix(c(a[i],b[i],d[i],e[i]), ncol = 2, nrow = 2)
}
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