Typescript Interface: Exactly one optional parameter is required

Question

I'd like to define an interface that allows you to supply content OR content_object but not both. You have to define one or the other. What is the simplest way to achieve this in TypeScript? I know I could say that content is string | object string | object , but the rest of my code benefits if I can define it as described instead.

interface IModal {
    content?: string;
    content_object?: object;
}

Answer 1

type IModal = { content: string; content_object?: undefined } |
              { content_object: object; content?: undefined }

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