Issues with path() in urls.py in django 2.0.5

Question

I am trying to do the following thing in urls.py but Django 2.0.5 doesn't seem to support url(). Instead of it, I used path() but still, its throwing invalid syntax error. Can someone give a clearer picture of path() as it seems to be not supporting regex.

Providing the code here:

from django.contrib import admin
from django.urls import path

from .views import home_page

urlpatterns = [
    path('$', home_page)
    path('admin/', admin.site.urls),
]

Answer 1

You miss a , , and $ is unnecessary

from django.contrib import admin
from django.urls import path

from .views import home_page

urlpatterns = [
    path('', home_page),
    path('admin/', admin.site.urls),
]

Answer 2

If you prefer to use url instead of path , that will work just fine. You just have to import from django.conf.urls instead. So your import statement should look like this:

from django.conf.urls import url

Django says on their documentation page that this feature will likely be deprecated in future versions to re-path , however, url still works fine for me, and I'm running Django 2.0.7 ... so, I imagine it would work with yours as well. I guess because of this, with Django version 2 and above, it nows decides when it creates the boilerplate project that instead of importing urls from django.conf.urls , it imports path from django.urls . ( Note : PATH doesn't allow for regex)

What I typically do, is create an app specific urls.py . In that urls.py I'll import url from django.conf.urls and have my specific app level urls there:

from django.conf.urls import url
from app_name import views # have to import views

urlpatterns = [
    url(r'^$', views.index),
    url(r'^users$',views.users),
]

Then in the project level urls.py I'll add the include module as so I can link it to my app specific urls.py file:

from django.conf.urls import url, include
from django.contrib import admin
from app_name import views

urlpatterns = [
    url(r'^',include('app_name.urls')),
    url(r'^admin/', admin.site.urls),
]

( Note : If you have a separate folder in between such that the folder structure looks something like mainproject>apps>app_name> (settings.py, views.py, admin.py etc...) you will have to create an __init__.py file in the apps folder as so Django can recognize the module.

Answer 3

Django2 has 2 functions for URLconfs, path() , re_path() .

You can use regex paths (regular expression based paths) with re_path() , so remove $ and place , between two consecutive paths.

Note : Let suppose your app name is my_django_app created by python manage.py startapp my_django_app command.

I created a new Django app named my_django_app and tried, it works fine. I have the following code in my urls.py file.

"""my_django_proj URL Configuration

The `urlpatterns` list routes URLs to views. For more information please see:
    https://docs.djangoproject.com/en/2.0/topics/http/urls/
Examples:
Function views
    1. Add an import:  from my_app import views
    2. Add a URL to urlpatterns:  path('', views.home, name='home')
Class-based views
    1. Add an import:  from other_app.views import Home
    2. Add a URL to urlpatterns:  path('', Home.as_view(), name='home')
Including another URLconf
    1. Import the include() function: from django.urls import include, path
    2. Add a URL to urlpatterns:  path('blog/', include('blog.urls'))
"""
from django.contrib import admin
from django.urls import path
from my_django_app.views import home_page

urlpatterns = [
    path('', home_page),
    path('admin/', admin.site.urls),
]

References : https://docs.djangoproject.com/en/2.0/topics/http/urls/

django 2.0 - including urls file from an app to the root urls file

Thanks.

Answer 4

urlpatterns = [
    path('', home_page),
    path('admin/', admin.site.urls)
]

As stated in the above answers, the $ is unnecessary while using path() . You are getting a syntax error due to the comma after admin.site.urls) which should be removed.