urls.py in django

Question

Here is the problem, the urls.py file in a django project look like this:

urlpatterns = patterns('',
    ...
    url(r'^admin/', include(admin.site.urls)),
    url(r'^testapp/', include('testapp.urls')),  #Here is the problem.
)

And I got an app installed, it is called 'testapp', so I wrote the include('testapp.urls') in the patterns.

The problem is that, Why should I put the testapp.urls in the quotation marks? Cuz I tried to put it like this: url('r^testapp/', include(testapp.urls)) , it didn't work. Why?

Answer 1

Your must import app in urls.py

import testapp

urlpatterns = patterns('',
    ...
    url(r'^admin/', include(admin.site.urls)),
    url(r'^testapp/', include(testapp.urls)),
)

Answer 2

ad3w has answered your question. If you want to learn a little more about it check this out: http://www.djangobook.com/en/2.0/chapter08/