Maya Python: How do I get the scene name but not the path or extension

Question

I want to get just the scene name of the file that is currently open. Not the path or extension.

cmds.file(q=True, sn=True)

I cannot use the above as it returns the full path.

Thanks

Answer 1

the os module includes utilities for this:

 filepath = cmds.file(q=True, sn=True)
 filename = os.path.basename(filepath)
 raw_name, extension = os.path.splitext(filename)

Answer 2

cmds.file(q=True, sn=True, shn=True)

Answer 3

(I wanted to post this as a comment to 's answer, but I can't as I don't have the required reputation level) 答案的评论，但我不能，因为我没有所需的声誉级别）

's answer is the correct answer (using the Python 'os' module): 的答案是正确的答案（使用 Python 'os' 模块）：

filepath = cmds.file(q=True, sn=True)
filename = os.path.basename(filepath)
raw_name, extension = os.path.splitext(filename)

You can make it shorter by combining with 's answer (which gives the file name with extension, but in a single instruction instead of 2 as in 's answer):的答案（它给出带扩展名的文件名，但在单个指令中而不是在的答案中使用 2 ）来：

filename = cmds.file(q=True, sn=True, shn=True)
raw_name, extension = os.path.splitext(filename)

Answer 4

import os
# a= "Full File Path of the scene"
a= r"C:\Python36\Lib\site-packages\anytree\node\nodemixin.py"

print(os.path.split(a)[1].split('.')[0])

'nodemixin'

or

print(os.path.splitext(a)[0].split('\\')[-1])

'nodemixin'

Answer 5

When you use Python in Maya you can use the file command. When you split it based on / you will get a list as result, which you then just count from the rear [-1]. That gives you the current Maya scene file name as string.

cmds.file(q=True, sn=True).split('/')[-1]

Answer 6

This works fine:

import maya.cmds as cmds

scene = cmds.file(q=True, sn=True)

scene = scene.split('/')[-1]

print(scene)