I am executing ImageMagick command using PHP exec
function, it returns an error code 4
which probably
mean The system cannot open the file
when however I run same command in Windows terminal it works fine. I am using this below command to resize the image:
In terminal(working fine)
convert -resize 150^% ad.png res_ad.png
In PHP (returning error code 4)
exec(escapeshellcmd("convert -resize 150% $file_name.png res_$file_name.png"), $output2, $return2)
PS: I have checked and path of the image is correct.
I have only had a 1 or 0 returned from Imagemagick using php so I do not know were the 4 is coming from.
I have used similar code to yours but have never used escapeshellcmd in the exec. The exec is calling an external program and I am not sure you can use it there.
Try( notice the input image comes right after the convert in most cases ):
exec("convert $file_name.png -resize 150% res_$file_name.png");
You can validate your input and output image filenames before sending them to exec()
Different error reporting:
$array=array();
echo "<pre>";
exec("convert $file_name.png -resize 150% res_$file_name.png 2>&1", $array);
echo "<br>".print_r($array)."<br>";
echo "</pre>";
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