How to write xpath in selenium for Login link?

Question

<a href="/MIS/PreLog/UserLogin.aspx" target="_blank">Login</a

I was trying to write the xpath for the above Login Link but it was not working.

driver.findElement( By.xpath("//a[contains(@href,'/MIS/PreLog/UserLogin.aspx') and  @id='login']" ).click();    

Please give me the solution for this..

Answer 1

In your xpath,

driver.findElement( By.xpath("//a[contains(@href,'/MIS/PreLog/UserLogin.aspx') and  @id='login']" ).click(); 

I don't see any @id attribute.

Also, why go for xpath specifically? You can use driver.findElement(By.LinkText("Login"))

Edit 1 : Try this

driver.findElement( By.xpath("//*[contains(@href,'UserLogin') and text()='Login']" )).click();

Answer 2

您的代码中的定位符可以如下修改和编写，请检查是否可以正常工作，

driver.findElement( By.xpath("//*[contains(@href,'UserLogin') and text()='Login']" )).click();