I am trying to update a field in an object in my array.
My object (simplified) looks something like this:
{
"readableStructure": [
{
"ID": "1",
"Name": "Name 1",
"Description": "Adding, updating or removing users",
"IconName": "fas fa-users-cog"
},
{
"ID": "2",
"Name": "Name 2",
"Description": "Views overview",
"IconName": "fas fa-street-view"
},
{
"ID": "3",
"Name": "Name 3",
"Description": "Improvements to apps",
"IconName": "fas fa-broadcast-tower"
},
{
"ID": "4",
"Name": "Name 4",
"Description": "Managing badges",
"IconName": "fas fa-id-badge"
},
{
"ID": "5",
"Name": "Name 5",
"Description": "Art",
"IconName": "fas fa-hand-holding-heart"
}
]
}
and I call it like this:
prepareRepositories(this.props.primarySearchRepositories);
I can have several similar repos and I loop through them. And for each item in the array readableStructure
I am trying to add a property called QSString
using the following code.
prepareRepositories(repositories) {
const repos = repositories.map((repo, index) => {
const searchableColumns = ['Name', 'Description'];
const newRepo = [];
newRepo[0] = {};
newRepo[0].readableStructure = [];
newRepo[0].readableStructure = repo[0].readableStructure.map((item) => {
item.QSString = this.getSearchableString(item, searchableColumns) || 'blaha';
return item;
});
return newRepo;
});
return repos;
}
getSearchableString = (base, searchableColumns) => {
let searchables = [];
Object.keys(base).forEach((key) => {
if ((searchableColumns.indexOf(key) > -1) && (base[key] !== null) && (typeof base[key] !== 'object')) {
searchables.push(base[key]);
}
});
const searchableString = searchables.join(' ');
return searchableString;
}
However, when I do this the original object is modified and the QSString
property get set to the same thing for every repo.
What am I doing wrong?
Array.map does not change the original array, ie creates a new Array. However, any object in the Array continues to hold the same reference , hence, any change in object even inside map function will update the object in original array.
You need to create a copy for the object .
item = JSON.parse(JSON.stringify(item))
使用这个不会改变原始对象
JSON.parse(JSON.stringify(your_object))
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