websocket send parameter in connection?

Question

I have a scenario which I need to create a very simple text chat using nodejs and Websocket .

I have everything set up and working.

I now need to allow users to send a parameter in the websocket connection URL.

Like so: websocket = new WebSocket("ws://test-website.net:8080/?id=55");

in my reserach I came across quite a few similar questions and found out that I can pass the parameters in the URL like the example above.

However, none of them mentions or explains how to get this parameter ( 55 in this example ) in server.js

wss.on('connection', function(ws) {

///I need to get the parameter here////

});

Could someone please advice on this issue?

Thanks in advance.

Answer 1

In your websocket request handler, it is normally passed the web socket as the first argument; the incoming HTTP request is passed as a second argument:

webSocketServer.on('connection', function connection(ws_client_stream, incoming_request) {
  console.log(incoming_request.url);
});

From there, you can use url.parse to get the components of the URL, such as the query string that you are interested in.

Answer 2

For websocket library in nodejs (websocket.js npm) :

wsServer.on('request', function(request){
    var FullURL = request.resourceURL.query;
    console.log(FullURL);
    // . . your code  . . //
}

link = wss://localhost/?param=value
output

{ param : 'value' }

here request.resourceURL retuen a object

Url {
  protocol: null,
  slashes: null,
  auth: null,
  host: null,
  port: null,
  hostname: null,
  hash: null,
  search: '?id=65&encoding=text',
  query: { id: '65', encoding: 'text' },
  pathname: '/',
  path: '/?id=65&encoding=text',
  href: '/?id=65&encoding=text' }

Answer 3

If you're using 'websocket' lib, the following code retrieves your queryStrings:

wsServer.on('request', function(request) 
{
    console.log(request.resourceURL.query);
}

Note 1: You don't need to parse anything here.

Note 2: Though it has been answered years ago, this answer goes to those in case where people find the above-mentioned answer more complicated.