I have a list of employees as follows:
[Employee{id="1", NID="A123", wages=5000},
Employee{id="2", NID="B123", wages=1000},
Employee{id="3", NID="C123", wages=2000},
Employee{id="4", NID="C123", wages=3000}]
I need to be able to retrieve only the unique objects and where NID is the same, I need to retrieve the one with the max Id. So the final list should be like
[Employee{id="1", NID="A123", wages=5000},
Employee{id="2", NID="B123", wages=1000},
Employee{id="4", NID="C123", wages=3000}]
I know it is possible to do it with nested for loops but I want to do it with Java streams. I could find which employee are duplicate in the list by using the group by but I still can't figure how to get the list like above.
Map<String, List<Employee>> groupByNid = employeeList.stream().collect(Collectors.groupingBy(Employee::getNID));
Thanks to help.
Ashley
I propose the following:
Collection<Employee> filteredEmployees = employeeList.stream()
.collect(Collectors.toMap(
Employee::getNID, Function.identity(),
BinaryOperator.maxBy(Comparator.comparing(Employee::getID))
)).values();
You can collect to map, using the NID
field for keys, and then selecting the highest ID
field in the merge function:
List<Employee> employeeList = ...;
Collection<Employee> uniqueEmployees = employeeList.stream()
.collect(Collectors.toMap(Employee::getNID,
Function.identity(),
(e1,e2) -> e1.getID().compareTo(e2.getID()) > 0 ? e1: e2)
).values();
You can do it like so,
Collection<Employee> emps = employees.stream()
.collect(Collectors.collectingAndThen(Collectors.toMap(Employee::getNID, Function.identity(),
(e1, e2) -> e1.getId().compareTo(e2.getId()) > 0 ? e1 : e2), m -> m.values()));
Try This:
List<Employee> list = new ArrayList<>();
list.add(new Employee(1,"A123",5000));
list.add(new Employee(2,"B123",1000));
list.add(new Employee(3,"C123",2000));
list.add(new Employee(4,"C123",2000));
Set<String> empSet = new HashSet<>();
list.removeIf(p -> !empSet.add(p.getNid()));
list.forEach(emp->System.out.println(emp.getId() +" : "+emp.getNid()+" :"+emp.getWage()));
You can do it like:
employeeList.stream().collect(Collectors.toMap(
Employee::getNID, r -> r, (e1, e2) -> e1.getId().compareTo(e2.getId()) > 0 ? e1 : e2));
@Test
public void t() {
Employee e1 = new Employee(1, "A123", 400);
Employee e2 = new Employee(2, "A123", 400);
List<Employee> list = Arrays.asList(e1,e2);
list = list.stream().filter(distinctByNid(Employee::getNid)).collect(Collectors.toList());
System.out.println(list);
}
// use a thread safe set to dedup
public static <T> Predicate<T> distinctByNid(Function<? super T, ?> keyExtractor) {
Set<Object> seen = ConcurrentHashMap.newKeySet();
return t -> seen.add(keyExtractor.apply(t));
}
static class Employee {
private int id;
private String nid;
private int wages;
public Employee(int id, String nid, int wages) {
this.id = id;
this.nid = nid;
this.wages = wages;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getNid() {
return nid;
}
public void setNid(String nid) {
this.nid = nid;
}
public int getWages() {
return wages;
}
public void setWages(int wages) {
this.wages = wages;
}
@Override
public String toString() {
return "Employee{" +
"id=" + id +
", nid='" + nid + '\'' +
", wages=" + wages +
'}';
}
}
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