Our API has a model defined:
class Job(models.Model):
file = models.FileField('File')
xml = models.FileField('XML')
There is a basic serializer:
class XmlSerializer(serializers.ModelSerializer)
file = serializers.FileField(read_only=True)
xml = serializers.FileField(required=True)
class Meta:
model = Job
fields = '__all__'
We don't want to change the file
but we do want to change the xml
field. The xml is uploaded by a system that doesn't know the primary key. Of course we need this to update the model.
I have the following code at the moment:
class ProcessXml(mixins.CreateModelMixin, generics.GenericAPIView):
serializer_class = XmlSerializer
def post(self, request, format=None):
pk = 200
serializer = XmlSerializer(request.data)
return Response({})
pk = 200
serves as an example instead of the code we use to parse the xml. I know this doesn't work but it's to show my intention (more or less).
I have tried to use
id = serializers.SerializerMethodField()
def get_id(self, obj):
return 200
without success.
How do I get this primary key into the the serializer?
I was making it much too difficult. The solution was pretty easy.
class ProcessXml(mixins.CreateModelMixin, generics.GenericAPIView):
serializer_class = XmlSerializer
def post(self, request, format=None):
id = magic_xml_parser_function()
job = get_object_or_404(Job, pk=id)
serializer = XmlSerializer(job, data=request.data)
if serializer.is_valid():
serializer.save()
return Response(serializer.data)
else:
return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)
magic_xml_parser_function()
contains the id we found in the xml. This solved it for us.
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