I would like to replace the 0 with the string from the same column, previous row. Eg: 0 under Sheffield should read Sheffield. I am working with pandas.
file = file[['Branch', 'Type' ,'total']]
#replace NaN with 0
file.fillna(0).tail(6)
Out[48]:
Branch Type total
394 Sheffield Sum of Resend to Branch 0
395 0 Number of PV Enquiries 83
396 Wakefield Sum of Resend to Branch 0
397 0 Number of PV Enquiries 38
398 York Sum of Resend to Branch 1
399 0 Number of PV Enquiries 59
I have tried:
a) #create a series for that column and replace
branch = file.iloc[ :, 0]
branch.replace(0, branch(-1))
# why is this series not callable?
b)# I tried a loop in the dataframe
for item in file:
if "Branch" == 0:
replace(0, "Branch"[-1])
# I am unsure how to refer to the row above
Use replace
with the method ffill
file_df['Branch'].replace(to_replace='0', method='ffill', inplace=True)
>>> file_df
Branch Type total
394 Sheffield Sum of Resend to Branch 0
395 Sheffield Number of PV Enquiries 83
396 Wakefield Sum of Resend to Branch 0
397 Wakefield Number of PV Enquiries 38
398 York Sum of Resend to Branch 1
399 York Number of PV Enquiries 59
Or, since it looks like you already replaced the NaN
with 0
, you could omit that step and just use ffill
. ie if your original dataframe looks like:
>>> file_df
Branch Type total
394 Sheffield Sum of Resend to Branch 0
395 NaN Number of PV Enquiries 83
396 Wakefield Sum of Resend to Branch 0
397 NaN Number of PV Enquiries 38
398 York Sum of Resend to Branch 1
399 NaN Number of PV Enquiries 59
use:
file_df['Branch'].ffill(inplace=True)
Note that I called your dataframe file_df
rather than file
to not mask the python
builtin
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