I'm making an Ajax call to the controller when clicking on a Kendo button and return the model:
@(Html.Kendo().Button()
.Name("btnSubmit")
.HtmlAttributes(new { type = "button" })
.Icon("rotate")
.Content("View Details"))
<script>
$("#btnSubmit").click(function () {
$.ajax({
url: "/MyController/MyMethod/",
type: 'post',
dataType: "json",
contentType: 'application/json; charset=utf-8',
success: function (result) {
window.location.href = "@Url.Action("RedirectToView", "MyController", new { myModel = "data" })".replace("data", result);
}
})
});
</script>
The controller's method returns the model:
[AcceptVerbs(HttpVerbs.Post)]
public JsonResult MyMethod()
{
var reportDate = Session["FileDate"] == null ? DateTime.Now : Convert.ToDateTime(Session["FileDate"].ToString());
var myModel = new MyModel();
myModel.ColOfData = myModel.GetColOfData(reportDate);
return Json(myModel, JsonRequestBehavior.AllowGet);
}
When I debug my Ajax
function, result is undefined. The result should be assigned to MyModel, since I'm returning the model back to an Ajax
function. I need to pass that result to another method in the controller that would return my Partial View
containing the Grid:
public ActionResult RedirectToView(MyModel myModel)
{
return PartialView("_MyPartialView", myModel);
}
What am I doing wrong?
Your problem isn't related to kendo.
From your controller you have to return a json object like this
return Json(new {result=myModel});
And in your ajax result you will have your entire model.
After that from the code you provided I am afraid you can't pass your entire model in the url of your GET.
You could probably pass the model Id like that
window.location.href = "@Url.Action("RedirectToView", "MyController", new { id= "modelId" })".replace("modelId", result.Id);
And make your action something like that
public ActionResult RedirectToView(string id){
// Get the model data you want .....
return PartialView("_MyPartialView", myModel);
}
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