Python: Finding the name of a enum class

Question

Given the following python code:

class Random_Skew_Enum( Enum ):
    NO_SKEW      = 0
    SKEW_LEFT_01 = 1
    SKEW_LEFT_02 = 2
    SKEW_LEFT_03 = 3
    SKEW_LEFT_04 = 4
    SKEW_LEFT_05 = 5
    SKEW_LEFT_06 = 6
    SKEW_RIGHT_01 = 7
    SKEW_RIGHT_02 = 8
    SKEW_RIGHT_03 = 9
    SKEW_RIGHT_04 = 10
    SKEW_RIGHT_05 = 11
    SKEW_RIGHT_06 = 12

    def _Convert ( self, enumeration ):

        text_to_enumeration = {}
        enumeration_name = ""

        def Do_Convert( self, value ):

            result = text_to_enumeration.get( value )
            if result is None:
                raise CCS_Enumeration_Error( "The enumeration '{0:s}' does not contain the value '{1:s}.".format( enumeration_name, value ) )
            return result

        enumeration_name = enumerate.name
        for enumerate in enumeration:
            match_data = self._split_enumeration.search( enumerate_name )
            new_key = match_data.group( 3 ).upper().strip()
            text_to_enumeration.update( dict( [ new_key, enumerate ] ))
        return Do_Convert

if I then code :

_Convert_Text_To_Random_Skew = self._Convert ( Random_Skew_Enum )

The line

enumeration_name = enumerate.name

generates an exception, I have tried other method to extract the name of the class from the parameter enumeration but with no effect, Can some one help?

Answer 1

The correct attribute to access the name of an object ( if it has one ) is __name__ .

If you want the class name, you would need type(enumerate).__name__ (or enumerate.__class__.__name__ if you're using old-style classes).