I have an matrix with hexadecimal number, like that:
[,1] [,2] [,3]
[1,] "FA" "F8" "D0"
[2,] "CE" "17" "6A"
[3,] "0E" "D6" "22"
If I try convert to binary, with hex2bin(matrix) (library BMS)
give me:
[1] 1 1 1 1 1 0 1 0 0 0 0 0 1 1 0 0 1 1 1 0 0 0 0 0 0 0 0 0 1 1 1 0 0 0 0 0 1 0 1 1 1 1 1 0 0 0 0 0 1 1 1 1 1 0 0 0 0 0 0 0 0
[62] 0 0 1 0 1 1 1 0 0 0 0 1 1 0 1 0 1 1 0 0 0 0 0 0 1 1 0 0 0 1 0 0 0 0 0 1 1 0 1 0 0 0 0 0 0 0 0 0 1 1 0 1 0 1 0 0 0 0 0 0 0
[123] 1 0 0 0 1 0 0 0 0 0 1 1 1 1 1 0 1 0 0 0 0 0 1 0 0 1 0 1 1 0 0 0 0 0 0 1 1 1 1 1 0 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0
[184] 1 0 0 0 1
But need a matrix.
Maybe like this? I convert to decimal integer using the built-in strtoi
, then take cues from Converting decimal to binary for getting to binary.
m = matrix(c("FA", "F8", "D0",
"CE", "17", "6A",
"0E", "D6", "22"), 3)
m[] = R.utils::intToBin(strtoi(m, base = 16L))
m
# [,1] [,2] [,3]
# [1,] "11111010" "11001110" "00001110"
# [2,] "11111000" "00010111" "11010110"
# [3,] "11010000" "01101010" "00100010"
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