Flag that indicates if Pycharm's is running the code with “Debug” or “Run”

Question

I've been wanting to run something only when I use "Debug" in PyCharm and make the code avoid it when it is run using "Run".

I saw some references to the __debug__ variable but it doesn't seem to change value as long as I run my code in PyCharm. I've seen some other comments referring to -O which I think, refer to running the code outside of the IDE.

I'm looking at creating something like this

if variable:
    print("Debug mode")
else:
    print("Run mode")

Answer 1

I would see if sys.gettrace() would work, like this:

import sys

if sys.gettrace() is None:
    print("Run Mode")
else: print("Debug Mode")

The documentation on gettrace is HERE , and should work with most implementations/IDEs. I also use Pycharm (Community and Professional) and use this to separate debugging logic.

Answer 2

PyCharm's debugger is merged with PyDev's, so you can use:

import sys

if "pydevd" in sys.modules: 
    print("Debug mode")
else:
    print("Run mode")