I'm getting the shape of a TensofFlow tensor as:
(?,)
This answer says that the ?
means that the dimension is not fixed in the graph and it can vary between run calls.
What does the ?
mean in conjuction with the trailing comma?
Documentation chapter and verse would be appreciated. I find syntax very difficult to google.
The comma means that the dimension is represented as a 1-elem tuple instead an int.
Each tensor, when created, is by default a n-dim:
import tensorflow as tf
t = tf.constant([1, 1, 1])
s = tf.constant([[1, 1, 1],[2,2,2]])
print("0) ", tf.shape(t))
print("1) ", tf.shape(s))
0) Tensor("Shape_28:0", shape=(1,), dtype=int32)
1) Tensor("Shape_29:0", shape=(2,), dtype=int32)
However, you can reshape it to get a more "whole" shape (ie n X m / n X m X r... dim):
print("2) ", tf.reshape(t, [3,1]))
print("3) ", tf.reshape(s, [2,3]))
2) Tensor("Reshape_12:0", shape=(3, 1), dtype=int32)
3) Tensor("Reshape_13:0", shape=(2, 3), dtype=int32)
Use tf.shape(tensor)[0]
to get a scalar tensor with the variable dimension. It is useful if you then need to reshape. tensor.get_shape().as_list()[0]
generates None for shapes with (?, ... ). This is usually the position for the batch size when training models.
Reference: TF Issues
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