I'm a newbie to the random forest (as well as python). I'm using random forest classifier, the dataset is defined 't2002'.
t2002.column
So here are the columns:
Index(['IndividualID', 'ES2000_B01ID', 'NSSec_B03ID', 'Vehicle',
'Age_B01ID',
'IndIncome2002_B02ID', 'MarStat_B01ID', 'EcoStat_B03ID',
'MainMode_B03ID', 'TripStart_B02ID', 'TripEnd_B02ID',
'TripDisIncSW_B01ID', 'TripTotalTime_B01ID', 'TripTravTime_B01ID',
'TripPurpFrom_B01ID', 'TripPurpTo_B01ID'],
dtype='object')
I'm using codes as below to run the classifier:
from sklearn.ensemble import RandomForestClassifier
from sklearn.metrics import make_scorer, accuracy_score
from sklearn.model_selection import GridSearchCV
from sklearn.model_selection import train_test_split
X_all = t2002.drop(['MainMode_B03ID'],axis=1)
y_all = t2002['MainMode_B03ID']
p = 0.2
X_train,X_test, y_train, y_test = train_test_split(X_all,y_all,test_size=p,
random_state=23)
clf = RandomForestClassifier()
acc_scorer = make_scorer(accuracy_score)
parameters = {
} # parameter is blank
grid_obj = GridSearchCV(clf,parameters,scoring=acc_scorer)
grid_obj = grid_obj.fit(X_train,y_train)
clf = grid_obj.best_estimator_
clf.fit(X_train,y_train)
predictions = clf.predict(X_test)
print(accuracy_score(y_test,predictions))
In this case, how could I use pandas to generate a crosstab (like a table) to show the detailed prediction results?
Thanks in advance!
you can first create a confusion matrix using sklearn and then convert it to pandas data frame.
from sklearn.metrics import confusion_matrix
#creating confusion matrix as array
confusion = confusion_matrix(t2002['MainMode_B03ID'].tolist(),predictions)
#converting to df
new_df = pd.DataFrame(confusion,
index = t2002['MainMode_B03ID'].unique(),
columns = t2002['MainMode_B03ID'].unique())
Its easy to show all the predicted results using pandas. Use cv_results_
as described in docs .
import pandas as pd
results = pd.DataFrame(clf.cv_results_) # clf is the GridSearchCV object
print(results.head())
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