I have this csv file:
A,0,10
B,20,.66
C,2,.72
D,1,.42
E,0,0
F,0,0
G,2,.56
I need to sort that based on the 3rd column so it will look like this:
A,0,10
C,2,.72
B,20,.66
G,2,.56
D,1,.42
E,0,0
F,0,0
I have tried with:
sort -t, -V -k3 input.txt
but its not giving the correct result. Any suggestion?
Based on below answer I have tried:
sort -t, -nr -k3 input.txt
but that gives:
C,2,.72
B,20,.66
G,2,.56
D,1,.42
A,0,10
F,0,0
E,0,0
which is not the expected result as I provided above.
Based on this: https://unix.stackexchange.com/questions/292087/how-do-i-get-bc-to-start-decimal-fractions-with-a-leading-zero
I am now prefixing with 0 and that gives the correct result when sorting.
using numeric sort will do the trick:
sort -t, -nr -k3 1.txt
You are using Version sort which is why you are getting the ouput that you are getting.
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