Find two numbers from a list that add up to a specific number

Question

This is super bad and messy, I am new to this, please help me.

Basically, I was trying to find two numbers from a list that add up to a target number.

I have set up an example with lst = [2, 4, 6, 10] and a target value of target = 8 . The answer in this example would be (2, 6) and (6, 2) .

Below is my code but it is long and ugly and I am sure there is a better way of doing it. Can you please see how I can improve from my code below?

from itertools import product, permutations

numbers = [2, 4, 6, 10]
target_number = 8

two_nums = (list(permutations(numbers, 2)))
print(two_nums)

result1 = (two_nums[0][0] + two_nums[0][1])
result2 = (two_nums[1][0] + two_nums[1][1])
result3 = (two_nums[2][0] + two_nums[2][1])
result4 = (two_nums[3][0] + two_nums[3][1])
result5 = (two_nums[4][0] + two_nums[4][1])
result6 = (two_nums[5][0] + two_nums[5][1])
result7 = (two_nums[6][0] + two_nums[6][1])
result8 = (two_nums[7][0] + two_nums[7][1])
result9 = (two_nums[8][0] + two_nums[8][1])
result10 = (two_nums[9][0] + two_nums[9][1])

my_list = (result1, result2, result3, result4, result5, result6, result7, result8, result9, result10)
print (my_list)

for i in my_list:
  if i == 8:
print ("Here it is:" + str(i))

Answer 1

This is super bad and messy, I am new to this, please help me.

Basically, I was trying to find two numbers from a list that add up to a target number.

I have set up an example with lst = [2, 4, 6, 10] and a target value of target = 8 . The answer in this example would be (2, 6) and (6, 2) .

Below is my code but it is long and ugly and I am sure there is a better way of doing it. Can you please see how I can improve from my code below?

from itertools import product, permutations

numbers = [2, 4, 6, 10]
target_number = 8

two_nums = (list(permutations(numbers, 2)))
print(two_nums)

result1 = (two_nums[0][0] + two_nums[0][1])
result2 = (two_nums[1][0] + two_nums[1][1])
result3 = (two_nums[2][0] + two_nums[2][1])
result4 = (two_nums[3][0] + two_nums[3][1])
result5 = (two_nums[4][0] + two_nums[4][1])
result6 = (two_nums[5][0] + two_nums[5][1])
result7 = (two_nums[6][0] + two_nums[6][1])
result8 = (two_nums[7][0] + two_nums[7][1])
result9 = (two_nums[8][0] + two_nums[8][1])
result10 = (two_nums[9][0] + two_nums[9][1])

my_list = (result1, result2, result3, result4, result5, result6, result7, result8, result9, result10)
print (my_list)

for i in my_list:
  if i == 8:
print ("Here it is:" + str(i))

Answer 2

This is super bad and messy, I am new to this, please help me.

Basically, I was trying to find two numbers from a list that add up to a target number.

I have set up an example with lst = [2, 4, 6, 10] and a target value of target = 8 . The answer in this example would be (2, 6) and (6, 2) .

Below is my code but it is long and ugly and I am sure there is a better way of doing it. Can you please see how I can improve from my code below?

from itertools import product, permutations

numbers = [2, 4, 6, 10]
target_number = 8

two_nums = (list(permutations(numbers, 2)))
print(two_nums)

result1 = (two_nums[0][0] + two_nums[0][1])
result2 = (two_nums[1][0] + two_nums[1][1])
result3 = (two_nums[2][0] + two_nums[2][1])
result4 = (two_nums[3][0] + two_nums[3][1])
result5 = (two_nums[4][0] + two_nums[4][1])
result6 = (two_nums[5][0] + two_nums[5][1])
result7 = (two_nums[6][0] + two_nums[6][1])
result8 = (two_nums[7][0] + two_nums[7][1])
result9 = (two_nums[8][0] + two_nums[8][1])
result10 = (two_nums[9][0] + two_nums[9][1])

my_list = (result1, result2, result3, result4, result5, result6, result7, result8, result9, result10)
print (my_list)

for i in my_list:
  if i == 8:
print ("Here it is:" + str(i))

Answer 3

This is super bad and messy, I am new to this, please help me.

Basically, I was trying to find two numbers from a list that add up to a target number.

I have set up an example with lst = [2, 4, 6, 10] and a target value of target = 8 . The answer in this example would be (2, 6) and (6, 2) .

Below is my code but it is long and ugly and I am sure there is a better way of doing it. Can you please see how I can improve from my code below?

from itertools import product, permutations

numbers = [2, 4, 6, 10]
target_number = 8

two_nums = (list(permutations(numbers, 2)))
print(two_nums)

result1 = (two_nums[0][0] + two_nums[0][1])
result2 = (two_nums[1][0] + two_nums[1][1])
result3 = (two_nums[2][0] + two_nums[2][1])
result4 = (two_nums[3][0] + two_nums[3][1])
result5 = (two_nums[4][0] + two_nums[4][1])
result6 = (two_nums[5][0] + two_nums[5][1])
result7 = (two_nums[6][0] + two_nums[6][1])
result8 = (two_nums[7][0] + two_nums[7][1])
result9 = (two_nums[8][0] + two_nums[8][1])
result10 = (two_nums[9][0] + two_nums[9][1])

my_list = (result1, result2, result3, result4, result5, result6, result7, result8, result9, result10)
print (my_list)

for i in my_list:
  if i == 8:
print ("Here it is:" + str(i))

Answer 4

This is super bad and messy, I am new to this, please help me.

Basically, I was trying to find two numbers from a list that add up to a target number.

I have set up an example with lst = [2, 4, 6, 10] and a target value of target = 8 . The answer in this example would be (2, 6) and (6, 2) .

Below is my code but it is long and ugly and I am sure there is a better way of doing it. Can you please see how I can improve from my code below?

from itertools import product, permutations

numbers = [2, 4, 6, 10]
target_number = 8

two_nums = (list(permutations(numbers, 2)))
print(two_nums)

result1 = (two_nums[0][0] + two_nums[0][1])
result2 = (two_nums[1][0] + two_nums[1][1])
result3 = (two_nums[2][0] + two_nums[2][1])
result4 = (two_nums[3][0] + two_nums[3][1])
result5 = (two_nums[4][0] + two_nums[4][1])
result6 = (two_nums[5][0] + two_nums[5][1])
result7 = (two_nums[6][0] + two_nums[6][1])
result8 = (two_nums[7][0] + two_nums[7][1])
result9 = (two_nums[8][0] + two_nums[8][1])
result10 = (two_nums[9][0] + two_nums[9][1])

my_list = (result1, result2, result3, result4, result5, result6, result7, result8, result9, result10)
print (my_list)

for i in my_list:
  if i == 8:
print ("Here it is:" + str(i))

Answer 5

This is super bad and messy, I am new to this, please help me.

Basically, I was trying to find two numbers from a list that add up to a target number.

I have set up an example with lst = [2, 4, 6, 10] and a target value of target = 8 . The answer in this example would be (2, 6) and (6, 2) .

Below is my code but it is long and ugly and I am sure there is a better way of doing it. Can you please see how I can improve from my code below?

from itertools import product, permutations

numbers = [2, 4, 6, 10]
target_number = 8

two_nums = (list(permutations(numbers, 2)))
print(two_nums)

result1 = (two_nums[0][0] + two_nums[0][1])
result2 = (two_nums[1][0] + two_nums[1][1])
result3 = (two_nums[2][0] + two_nums[2][1])
result4 = (two_nums[3][0] + two_nums[3][1])
result5 = (two_nums[4][0] + two_nums[4][1])
result6 = (two_nums[5][0] + two_nums[5][1])
result7 = (two_nums[6][0] + two_nums[6][1])
result8 = (two_nums[7][0] + two_nums[7][1])
result9 = (two_nums[8][0] + two_nums[8][1])
result10 = (two_nums[9][0] + two_nums[9][1])

my_list = (result1, result2, result3, result4, result5, result6, result7, result8, result9, result10)
print (my_list)

for i in my_list:
  if i == 8:
print ("Here it is:" + str(i))

Answer 6

This is super bad and messy, I am new to this, please help me.

Basically, I was trying to find two numbers from a list that add up to a target number.

I have set up an example with lst = [2, 4, 6, 10] and a target value of target = 8 . The answer in this example would be (2, 6) and (6, 2) .

Below is my code but it is long and ugly and I am sure there is a better way of doing it. Can you please see how I can improve from my code below?

from itertools import product, permutations

numbers = [2, 4, 6, 10]
target_number = 8

two_nums = (list(permutations(numbers, 2)))
print(two_nums)

result1 = (two_nums[0][0] + two_nums[0][1])
result2 = (two_nums[1][0] + two_nums[1][1])
result3 = (two_nums[2][0] + two_nums[2][1])
result4 = (two_nums[3][0] + two_nums[3][1])
result5 = (two_nums[4][0] + two_nums[4][1])
result6 = (two_nums[5][0] + two_nums[5][1])
result7 = (two_nums[6][0] + two_nums[6][1])
result8 = (two_nums[7][0] + two_nums[7][1])
result9 = (two_nums[8][0] + two_nums[8][1])
result10 = (two_nums[9][0] + two_nums[9][1])

my_list = (result1, result2, result3, result4, result5, result6, result7, result8, result9, result10)
print (my_list)

for i in my_list:
  if i == 8:
print ("Here it is:" + str(i))

Answer 7

This is super bad and messy, I am new to this, please help me.

Basically, I was trying to find two numbers from a list that add up to a target number.

I have set up an example with lst = [2, 4, 6, 10] and a target value of target = 8 . The answer in this example would be (2, 6) and (6, 2) .

Below is my code but it is long and ugly and I am sure there is a better way of doing it. Can you please see how I can improve from my code below?

from itertools import product, permutations

numbers = [2, 4, 6, 10]
target_number = 8

two_nums = (list(permutations(numbers, 2)))
print(two_nums)

result1 = (two_nums[0][0] + two_nums[0][1])
result2 = (two_nums[1][0] + two_nums[1][1])
result3 = (two_nums[2][0] + two_nums[2][1])
result4 = (two_nums[3][0] + two_nums[3][1])
result5 = (two_nums[4][0] + two_nums[4][1])
result6 = (two_nums[5][0] + two_nums[5][1])
result7 = (two_nums[6][0] + two_nums[6][1])
result8 = (two_nums[7][0] + two_nums[7][1])
result9 = (two_nums[8][0] + two_nums[8][1])
result10 = (two_nums[9][0] + two_nums[9][1])

my_list = (result1, result2, result3, result4, result5, result6, result7, result8, result9, result10)
print (my_list)

for i in my_list:
  if i == 8:
print ("Here it is:" + str(i))

Answer 8

This is super bad and messy, I am new to this, please help me.

Basically, I was trying to find two numbers from a list that add up to a target number.

I have set up an example with lst = [2, 4, 6, 10] and a target value of target = 8 . The answer in this example would be (2, 6) and (6, 2) .

Below is my code but it is long and ugly and I am sure there is a better way of doing it. Can you please see how I can improve from my code below?

from itertools import product, permutations

numbers = [2, 4, 6, 10]
target_number = 8

two_nums = (list(permutations(numbers, 2)))
print(two_nums)

result1 = (two_nums[0][0] + two_nums[0][1])
result2 = (two_nums[1][0] + two_nums[1][1])
result3 = (two_nums[2][0] + two_nums[2][1])
result4 = (two_nums[3][0] + two_nums[3][1])
result5 = (two_nums[4][0] + two_nums[4][1])
result6 = (two_nums[5][0] + two_nums[5][1])
result7 = (two_nums[6][0] + two_nums[6][1])
result8 = (two_nums[7][0] + two_nums[7][1])
result9 = (two_nums[8][0] + two_nums[8][1])
result10 = (two_nums[9][0] + two_nums[9][1])

my_list = (result1, result2, result3, result4, result5, result6, result7, result8, result9, result10)
print (my_list)

for i in my_list:
  if i == 8:
print ("Here it is:" + str(i))

Answer 9

n is the sum desired, L is the List. Basically you enter inside the loop and from that no to end of list iterate through the next loop. If L[i],L[j] indexes in list adds up to n and if L[i]!=L[j] print it.

numbers=[1,2,3,4,9,8,5,10,20,30,6]
def two_no_summer(n,L):
     for i in range(0,len(L)):
         for j in range(i,len(L)):
             if (L[i]+L[j]==n) & (L[i]!=L[j]):
                  print(L[i],L[j])

Execution: https://i.stack.imgur.com/Wu47x.jpg