I've got an interesting one for you all.
I'm looking to first: Look through the ID column and identify duplicate values. Once those are identified, the code should go through the income of the duplicated values and keep the row with the larger income.
So if there are three ID values of 2, it will look for the one with the highest income and keep that row.
ID Income 1 98765 2 3456 2 67 2 5498 5 23 6 98 7 5645 7 67871 9 983754 10 982 10 2374 10 875 10 4744 11 6853
I know its as easy as subsetting based on a condition, but I don't know how to remove the rows based on if the income in one cell is greater than the other.(Only done if the id's match)
I was thinking of using an ifelse statement to create a new column to identify duplicates (through subsetting or not) then use the new column's values to ifelse again to identify the larger income. From there I can just subset based on the new columns I have created.
Is there a faster, more efficient way of doing this?
The outcome should look like this.
ID Income 1 98765 2 5498 5 23 6 98 7 67871 9 983754 10 4744 11 6853
Thank you
We can slice
the rows by checking the highest value in 'Income' grouped by 'ID'
library(dplyr)
df1 %>%
group_by(ID) %>%
slice(which.max(Income))
Or using data.table
library(data.table)
setDT(df1)[, .SD[which.max(Income)], by = ID]
Or with base R
df1[with(df1, ave(Income, ID, FUN = max) == Income),]
# ID Income
#1 1 98765
#4 2 5498
#5 5 23
#6 6 98
#8 7 67871
#9 9 983754
#13 10 4744
#14 11 6853
df1 <- structure(list(ID = c(1L, 2L, 2L, 2L, 5L, 6L, 7L, 7L, 9L, 10L,
10L, 10L, 10L, 11L), Income = c(98765L, 3456L, 67L, 5498L, 23L,
98L, 5645L, 67871L, 983754L, 982L, 2374L, 875L, 4744L, 6853L)),
class = "data.frame", row.names = c(NA,
-14L))
order
with duplicated
( Base R)
df=df[order(df$ID,-df$Income),]
df[!duplicated(df$ID),]
ID Income
1 1 98765
4 2 5498
5 5 23
6 6 98
8 7 67871
9 9 983754
13 10 4744
14 11 6853
Here is another dplyr
method. We can arrange the column and then slice the data frame for the first row.
library(dplyr)
df2 <- df %>%
arrange(ID, desc(Income)) %>%
group_by(ID) %>%
slice(1) %>%
ungroup()
df2
# # A tibble: 8 x 2
# ID Income
# <int> <int>
# 1 1 98765
# 2 2 5498
# 3 5 23
# 4 6 98
# 5 7 67871
# 6 9 983754
# 7 10 4744
# 8 11 6853
DATA
df <- read.table(text = "ID Income
1 98765
2 3456
2 67
2 5498
5 23
6 98
7 5645
7 67871
9 983754
10 982
10 2374
10 875
10 4744
11 6853",
header = TRUE)
Group_by and summarise from dplyr would work too
df1 %>%
group_by(ID) %>%
summarise(Income=max(Income))
ID Income
<int> <dbl>
1 1 98765.
2 2 5498.
3 5 23.
4 6 98.
5 7 67871.
6 9 983754.
7 10 4744.
8 11 6853.
Using sqldf
: Group by ID
and select the corresponding max Income
library(sqldf)
sqldf("select ID,max(Income) from df group by ID")
Output:
ID max(Income)
1 1 98765
2 2 5498
3 5 23
4 6 98
5 7 67871
6 9 983754
7 10 4744
8 11 6853
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