How to find an array which is having atleast 3 values greater than 4 in php

Question

$arr = array(4, 2, 3, 4, 5);

How to find the array is containing atleast 3 values which are greater than or equal to 4?

I just want to maintain a flag that the array holds 3 values equal to or greater than 4.

Answer 1

Using array_reduce :

$total = array_reduce($arr, function($num, $val) {
  if ($val >= 4) $num++;
  return $num;
}, 0);

Answer 2

Iterate the array, set the value to a counter.

$counter = 0;
$hasMoreThan3 = false;
foreach($array as $element) {
    if($element > 3) {
        $counter++;
        if($counter >= 3) {
            $hasMoreThan3 = true;
            break;
        }
    }
}

var_dump($hasMoreThan3);

If the array is short, you can filter

count(array_filter($array, function($e) {
    return $e > 3;
}));

Answer 3

You could do it like this :

$arr = array(4, 2, 3, 4, 5);
var_dump(threeValuesOver($arr, 3));
function threeValuesOver($array,$value){
    $counter = 0;
    foreach($array as $entry){
        if($entry > $value) $counter++;
        if($counter >= 3) return true;
    }
    return false;
}

Answer 4

Here is fast simple code:

$arr = array(4, 2, 3, 4, 5);
$countval = 0;
foreach($arr as $val) {
    $countval+=($val >=4)?1:0;
}
$flag = ($countval>2);

It will count values equal or greater 4 and if it counts 3 or more it will echo.

Try this another code:

$arr = array(4, 2, 3, 4, 5);
//--- 1
$arrdif = array(0, 1, 2, 3);
$flag = (count(array_diff($arr, $arrdif))==3);
//--- 2
rsort($arr, SORT_NUMERIC);
$flag = (array_search(3, $arr)==3);

Answer 5

This is the simple solution after optimizing 'msg' solution

$bool = array_reduce($arr, function($num, $val) {
  if ($val >= 4) $num++;
   return $num;
}, 0) >= 3;