new to programming.
I have a class in java and i'm trying to write this program but it's printing none-stop and it's even bugging my browser! (Im using an online ide)
my instructions: Q: how much do you love me? Below 10 : wrong answer equal to 10 and more = good answer
I know how to do it but I dont want the program to stop every time i write an answer. I want the program to keep running until i have a 10 +. So i can always input until it's 10+ out of 10.
this is my lines :
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner input = new Scanner (System.in);
System.out.println ("how much do you love me out of 10");
int num1 = input.nextInt();
while (true)
if (num1 <= 9) {
System.out.println("Wrong answer");
}
else {
System.out.println ("Good answer");
}
}
}
This should work:
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner (System.in);
System.out.println ("Out of 10, how much do you love me?");
int input = 0
while (input <= 9) {
input = scanner.nextInt();
if (input <= 9) {
System.out.println("Wrong answer");
} else {
System.out.println("Good answer");
}
}
}
}
Explanation: It loops until input is less not less than or equal to 9 ( while (input <= 9)
). Each time through the loop, it gets input and acts on it.
Hope this helps!
First off, you need to move the int num1 = input.nextInt();
statement inside your while loop, this will allow for a new input every time the while loop loops (iterates).
Second, if you are looking to run the program until num1 >= 10
, then you could implement it in two ways.
while(num1 < 10) {
num1 = input.nextInt();
if(num1 >= 10) {
System.out.println("Good answer");
} else {
System.out.println("Wrong answer");
}
}
or using the keyword break
,
while(true) {
num1 = input.nextInt();
if(num1 >= 10) {
System.out.println("Good answer");
break;
} else {
System.out.println("Wrong answer");
}
}
break
simply escapes the loop it resides in when called
Hoped this helped
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