scala- Read file from S3 bucket

Question

I want to read a specific file from S3 bucket. In my S3 bucket I will be having so many objects(directories and Sub directories). I want traverse through all the objects and have to read only that file.

I am trying below code:

val s3Client: AmazonS3Client = getS3Client()
    try {
      log.info("Listing objects from S3")
      var counter = 0

      val listObjectsRequest = new ListObjectsRequest()
        .withBucketName(bucketName)
        .withMaxKeys(2)
        .withPrefix("Test/"+"Client_cd" + "/"+"DM1"+"/")
        .withMarker("Test/"+"Client_cd" + "/"+"DM1"+"/")
      var objectListing: ObjectListing = null
      do {
        objectListing = s3Client.listObjects(listObjectsRequest)
        import scala.collection.JavaConversions._
        for (objectSummary <- objectListing.getObjectSummaries) {
          println( objectSummary.getKey + "\t" + StringUtils.fromDate(objectSummary.getLastModified))

        }
          listObjectsRequest.setMarker(objectListing.getNextMarker())
        }
        while (objectListing.isTruncated())

    }
    catch {
      case e: Exception => {
        log.error("Failed listing files. ", e)
        throw e
      }
    }

In this path I have to read only .gz files from latest month folders. File Path:

"Mybucket/Test/Client_cd/Dm1/20181010_xxxxx/*.gz"

Here, I have to pass Client_cd as parameter for particular client.

How to filter the objects and to get particular files?

Answer 1

如果您正在使用EMR或正确设置了S3配置，则还可以使用sc.textFile("s3://bucket/Test/Client_cd/Dm1/20181010_xxxxx/*.gz")