How to fix an unexpected end of file error in bash?

Question

The code saying that there is "unexpected end of file" error in line 16. Could someone please tell me my mistake?

#!/bin/bash

total=0
for i in `grep 01/Oct/2006 log.txt | cut -d' ' -f1 | sort | uniq -c | sort -n | tail`;
do if [[ $i =~ ^[0-9]+$ ]]; then
    total=$(( $total + $i )); fi

for i in `grep 01/Oct/2006 log.txt | cut -d' ' -f1 | sort | uniq -c | sort -rn | head -10 | tr -s ' ' | cut -d' ' -f2,3 | sed -E 's/(\S*) (\S*)/\2 - \1/' | nl -s'. '`;

do 
    if ! [[ $i =~ ^[0-9]+$ ]];
        then
            printf $i;
            printf " ";
        else
            printf " $i - $(echo "scale=0; $i * 100 / $total" | bc )%% \n" ;
    fi
done

Answer 1

Your first for loop lacks a done .

Here's a working version with improved formatting (but with all original flaws and bugs left inside, I just fixed the one issue asked for here):

#!/bin/bash

$total;
for i in $(
  grep 01/Oct/2006 log.txt | 
    cut -d' ' -f1 |
      sort |
        uniq -c |
          tail);
do
  if [[ $i =~ ^[0-9]+$ ]]
  then
    $total += $i
  fi
done

for i in $(
  grep 01/Oct/2006 log.txt |
    cut -d' ' -f1 |
      sort |
        uniq -c |
          sort -rn |
            head -10 |
              tr -s ' ' |
                cut -d' ' -f2,3 |
                  sed -E 's/(\S*) (\S*)/\2 - \1/' |
                    nl -s'. ')
do 
  if ! [[ $i =~ ^[0-9]+$ ]];
  then
    printf " $i - ";
  else
    printf " $i - 0$(echo "scale=0; $i / $total" | bc)%% " ;
  fi
done