How can I extract a column from pandas dataframe attach it to rows while keeping the other columns same.
This is my example dataset.
import pandas as pd
import numpy as np
df = pd.DataFrame({'ID': np.arange(0,5),
'sample_1' : [5,6,7,8,9],
'sample_2' : [10,11,12,13,14],
'group_id' : ["A","B","C","D","E"]})
The output I'm looking for is:
df2 = pd.DataFrame({'ID': [0, 1, 2, 3, 4, 0, 1, 2, 3, 4],
'sample_1' : [5,6,7,8,9,10,11,12,13,14],
'group_id' : ["A","B","C","D","E","A","B","C","D","E"]})
I have tried to slice the dataframe and concat using pd.concat
but it was giving NaN values.
My original dataset is large.
You could do this using stack
: Set the index to the columns you don't want to modify, call stack, sort by the "sample" column, then reset your index:
df.set_index(['ID','group_id']).stack().sort_values(0).reset_index([0,1]).reset_index(drop=True)
ID group_id 0
0 0 A 5
1 1 B 6
2 2 C 7
3 3 D 8
4 4 E 9
5 0 A 10
6 1 B 11
7 2 C 12
8 3 D 13
9 4 E 14
Using pd.wide_to_long
:
res = pd.wide_to_long(df, stubnames='sample_', i='ID', j='group_id')
res.index = res.index.droplevel(1)
res = res.rename(columns={'sample_': 'sample_1'}).reset_index()
print(res)
ID group_id sample_1
0 0 A 5
1 1 B 6
2 2 C 7
3 3 D 8
4 4 E 9
5 0 A 10
6 1 B 11
7 2 C 12
8 3 D 13
9 4 E 14
The function you are looking for is called melt
For example:
df2 = pd.melt(df, id_vars=['ID', 'group_id'], value_vars=['sample_1', 'sample_2'], value_name='sample_1')
df2 = df2.drop('variable', axis=1)
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