How to remove an element from array of literal objects

Question

您好，我正在尝试从数组数据中的每个对象中删除操作属性：

[{productName: "", ... action: ...,}, {productName: "", ...action:...} ...]

Answer 1

var arr  =[{productName: "bbbb", action: 'b'},
         {productName: "aa",action: 'a'}, 
         {productName: "tt",action: 't'}, 
         {productName: "vv",action: 'v'}]


arr = arr.map((d) => {delete d.action ; return d;});

Answer 2

1) With map(...) :

your_array.map(o => {'productName': o.productName})

NB that this is more elegant if you want to filter off lots of attributes, but more work if you just want to remove one.

2) With delete :

for (let i = 0; i < your_array.length; i++){
    delete your_array[i].action
}

Answer 3

Iterate over the array using map and destructure the object to keep only the required field

 var arr = [{ producet: 'xyz', action: 'abc', other: 'o' }, { producet: 'xyz', action: '123', other: 'o' }, { producet: 'xyz', action: 'sdf', other: 'o' }] const result = arr.map(({ action, ...rest }) => rest); console.log(result);

Answer 4

With ES6 you can use map with destructuring and rest parameters to separate out the object properties you want to retain, and the part you want to discard:

 const data = [{ id: 1, productName: "1", action: '' }, { id: 1, productName: "2", action: '' }]; let out = data.map(({ action, ...rest }) => rest); console.log(out);

Answer 5

Use array map It will return a new array.Inside map callback create a new object and populate only those fields that are required. Don't mutate the original array

 var arr = [{ productName: "1", action: '' }, { productName: "2", action: '' }]; let newArr = arr.map(function(item) { return Object.assign({}, { productName: item.productName }) }); console.log(newArr)

Answer 6

According to the docs you can use the delete operator.

A simple way to do this is to loop over your array arr and delete the property from each object.

for (var i = 0; i < arr.length; i++){
    delete arr[i].action;
}

This approach is slightly faster than other approaches such as map and for each .