For example, input is:
12 23 32 41 45
22 11 43
lines end with '\\n'
,
I want save nums to a[]
and b[]
;
a[] = {12, 23, 32, 41, 45}
b[] = {22, 11, 43}
The point is I DON'T KNOW how many number of each line.
If I know line1 n
numbers and line2 m
numbers, I will use "for loop", and no question.
Just like,
for(int i = 0; i < n; i++) scanf("%d", a+i);
for(int i = 0; i < m; i++) scanf("%d", b+i);
But, I DO NOT know n and m, How to do, guys?
If you would like to continue using a scanf approach, I would recommend the negated scanset %[^]
format specifier.
scanf("%[^\\n]", pointerToCharArray)
This should read in any number of characters up to but not including the character specified (which, in our case, is a newline). If you'd like to discard the newline, read it in as follows:
scanf("%[^\\n]\\n", pointerToCharArray)
A link to the reference page can be found below. The negated scanset specifier is included in the list:
http://www.cplusplus.com/reference/cstdio/scanf/
From this point, it is a simple matter to use strtok() to tokenize the output of the scanf into number arrays. If you are not familiar with strtok, another reference link is provided below:
http://www.cplusplus.com/reference/cstring/strtok/
I hope this helps!
Let us use the non standard getline
, a common library extension. @Abbott to read the entire line into allocated memory.
If an array is needed and its size determined at run-time, use a variable length array available in C99 and optionally in C11.
Make a function to count and maybe save the numbers. Use strto...()
functions for robust parsing.
size_t count_longs(char *line, long *dest) {
size_t count = 0;
char *s = line;
for (;;) {
char *endptr;
long num = strtol(s, &endptr, 10);
if (s == endptr) {
break; /// no conversion
}
s = endptr;
if (dest) {
dest[count] = num;
}
count++;
}
return count;
}
Sample code snippet
char *line = NULL;
size_t len = 0;
ssize_t nread = getline(&line, &len, stdin); // read the whole line
if (nread != -1) {
// successful read
long a[count_longs(line, NULL)]; // determine array size and use a
count_longs(line, a); // 2nd pass: assign array elements.
nread = getline(&line, &len, stdin);
if (nread != -1) {
// successful read
long b[count_longs(line, NULL)];
count_longs(line, b);
// Do something with a and b
}
}
free(line);
len = 0;
A solution that could potentially fit what OP asked for would be the code below. The solution reads an unspecified number of integer values & stores them in arr
. to break the loop/end input simply input a non-integer value. This could be further specified to search for a specific input etc.
int c = 0;
int *arr = NULL;
int *extArr = NULL;
int i = 0;
for (i = 0; scanf("%d", &c) == 1; i++)
{
extArr = (int*)realloc(arr, (i+1) * sizeof(int));
arr = extArr;
arr[i] = c;
}
free(arr);
I would, however personally go with a mix between the solution i provided & armitus answer(if i cant use getline
or similar) since reallocating memory for every single int value seems redundant to me.
Edit Since there has been some question about the code i provided and how to best use it in order to fulfill the OP's question. The codesnippet was supposed to showcase how one might create his own scanf-style function for unspecified number of integer inputs reading one full array at a time(in that case the free()
has to be omitted till one is done with the array(obviously).
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