R purrr map show column names in output

Question

I'm trying to run purrr map across vector inputs, and in the output i'd like the output columns to have meaningful names.

x <- c("a", "b")
y <- "end."

map_dfc(x, function(x) paste("pre ", x, y))

names(x) <- x
map_dfc(x, function(x) paste(x, y))

This is the output I expect, which has column names a and b :

# A tibble: 1 x 2
# a      b     
# <chr>  <chr> 
# pre  a end. pre  b end.

Is there a way to avoid the need to run

names(x) <- x

ie

x <- c("a", "b")
y <- "end."

map_dfc(x, function(x) paste("pre ", x, y))
# A tibble: 1 x 2
# a      b     
# <chr>  <chr> 

yields the data.frame/tibble with column names already attached?

I use map alot and often forget if the input vector has names or not.

Answer 1

One easy method is to have input elements named. This usually result in more consistent code.

library(purrr)
x <- setNames(c("a", "b"), nm = c("a", "b"))
# x <- setNames(nm = c("a", "b")) # this is short cut of above
y <- "end."
map_dfc(x, function(x) paste("pre ", x, y))

Answer 2

In addition to @RonakShah's comment suggesting setNames() , you can handle this without purrr::map() :

paste("pre ", x, y) %>% 
  as.list() %>%
  as.data.frame(col.names = x, stringsAsFactors = F)

Answer 3

The purrr way is to use set_names as in the comments, (although correct setNames seems to be replaced by set_names in purrr ):

map_dfc(set_names(x), function(x) paste("pre ", x, y))

With set_names you don't need to specify the new names if you use the default argument.