How to make javascript regular expression match any char and carriage return?
Question
I have a html file like below.
<body>
<p>Enter your phone number with area code and then click
Check The expected format is like</p>
<form action="#">
<input id="phone"><button onclick="testInfo(document.getElementById('phone'));">Check</button>
</form>
</body>
</html>
I use below script which can print right result.
fs.readFile('test.html', 'utf8', function (err, data) {
var re = /<p>[a-zA-Z1-9\s\r\n]*<\/p>/i;
var myArray = data.match(re);
console.log(myArray);
});
the result: '<p>Enter your phone number with area code and then click \\r\\n Check The expected format is like</p>'
But I want to use regular expresstion like below.
re = /<p>[.\r\n]*<\/p>/i;
But it print null. How to fix it? Why I can not use . to replace a-zA-Z1-9\\s thanks.
1 answers
solution1
0 2019-01-18 14:49:14
The reason is that a dot within a character class ( [...] ) looses its "superpowers" - meaning it is only a dot.
What you possibly want is re = /<p>[\\s\\S]+?<\\/p>/i; but please be warned that it is nod advisable to parse HTML structures with a regular expression:
let html = ` <body> <p>Enter your phone number with area code and then click Check The expected format is like</p> <form action="#"> <input id="phone"><button onclick="testInfo(document.getElementById('phone'));">Check</button> </form> </body> </html>`; re = /<p>[\\S\\s]+?<\\/p>/i; var myArray = html.match(re); console.log(myArray);
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