The following is incorrectly showing "null" for values of 0
, but I only want it to do that for exactly nil
.
package main
import (
"os"
"text/template"
)
type thing struct {
Value interface{}
}
func main() {
tmpl, _ := template.New("test").Parse("{{if .Value }} {{.Value}} {{else}} [null] {{end}}\n")
tmpl.Execute(os.Stdout, thing{Value: "hi"}) // outputs hi
tmpl.Execute(os.Stdout, thing{Value: nil}) // outputs [null]
tmpl.Execute(os.Stdout, thing{Value: 0}) // outputs [null] - should output 0
tmpl.Execute(os.Stdout, thing{Value: 2}) // outputs 2
}
Playground link: https://play.golang.org/p/Gg8uBCOb2vE
How do I make it show the value of 0
instead?
.Value
is an interface{}
which in the problem case contains an int
, but could contain anything.
Show default content in a template if an object is nil otherwise show based on the set property is close but not quite the same thing
I would just create a function that you pass to the template using template.Funcs
:
https://play.golang.org/p/anxW5ooGE7N
funcs := make(map[string]interface{})
funcs["isNotNull"] = func(t interface{}) bool {
return t != nil
}
tmpl, _ := template.New("test").Funcs(funcs).Parse("{{if isNotNull .Value }} {{.Value}} {{else}}[null] {{end}}\n")
tmpl.Execute(os.Stdout, thing{Value: "hi"}) // outputs hi
tmpl.Execute(os.Stdout, thing{Value: nil}) // outputs [null]
tmpl.Execute(os.Stdout, thing{Value: 0}) // outputs 0
tmpl.Execute(os.Stdout, thing{Value: 2}) // outputs 2
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