Im writting a OS in html, and my OS can support apps by specifying the main script, now i have two apps, one executing file1, and another, file2. And I have three files:
file1.js
function main() {
//this is a code
. . .
}
file2.js
function main() {
//this is another code
. . .
}
And i want to call just one of theirs function, the file1's function:
System.js
var System = {
/*
*Used Mode:
*
* var app = System.openApp(package);
*/
openApp:function(package) {
//starts the app:
var path = "/@APP:/" + package + "/app.xml";
console.log("Opening " + package + "...");
var xhttp = new XMLHttpRequest();
xhttp.open("GET", path, true);
xhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
console.log("The app \"" + xhttp.responseXML.getElementsByTagName("Manifest")[0].getElementsByTagName("AppName")[0].childNodes[0].nodeValue + "\" was successfully loaded!");
if (xhttp.responseXML.getElementsByTagName("Manifest")[0].getElementsByTagName("AppMode")[0].childNodes[0].nodeValue = "prompted") {
this.openMainAct();
}
}
};
xhttp.onerror = function() {
console.error("The app \"" + package + "\" was not found\n ERROR_CODE:" + xhttp.readyState);
};
xhttp.send();
//subfunctions:
/*
*Used Mode:
*
* app.setIcon("path/to/file.png");
*/
this.setIcon = function(icon) {
// @TODO: Making Icons, just ignore;
};
/*
*@DEPRECATED: Use the method "openAct"
*
*Used Mode:
* var MyAct = app.openMainAct();
*/
this.openMainAct = function() {
var a = document.createElement("script");
a.src = this.getAppMainSource;
document.body[0].appendChild(a);
//And HERE opens the main function!
};
//vars:
this.getManifest = xhttp.responseXML.getElementsByTagName("Manifest")[0];
this.getPackage = package;
this.getAppFolder = "/@APP:/" + package;
this.getAppMode = this.getManifest.getElementsByTagName("AppMode")[0];
this.getName = xhttp.responseXML.getElementsByTagName("Manifest")[0].getElementsByTagName("AppName")[0];
this.getJSource = this.getAppFolder + "/" + this.getManifest.getElentsByTagName("JSDir")[0];
this.getJSDir = this.getManifest.getElementsByTagName("JSDir")[0];
this.getVersion = this.getManifest.getElementsByTagName("Version")[0];
this.getAppMainSource = this.getJSource + "/" + this.getManifest.getElementsByTagName("AppMain")[0] + ".js";
this.getAppMain = this.getManifest.getElementsByTagName("AppMain")[0];
this.getPermissionGroup = this.getManifest.getElementsByTagName("AppPerm")[0];
this.getPermission = this.getPermissionGroup.getElementsByTagName("AddPerm");
}
};
But the main.js calls all functions!
As see below, we need to call a function to start a app:
var app = System.openApp("a.b.c");
And one folder with same name must exists!
This is my manifest:
<?xml version="1.0" encoding="utf-8" ?>
<Manifest>
<JSDir>JS</JSDir>
<Version>0.0.1</Version>
<AppName>Documentação de API do EDOS</AppName>
<AppMode>windowed</AppMode>
<AppMain>MainAct</AppMain>
<AppPerm>
<AddPerm>edos.permission.WRITE_APP</AddPerm>
<AddPerm>edos.permission.READ_APP</AddPerm>
</AppPerm>
</Manifest>
Sorry if i give too much info... PS: I dont want APIs!!
Export your functions at the bottom of your files. And import your functions at the top of your files.
When you import a function, that function will be available in that files scope
and accessible under the name you choose when you import it.
If you export the function as named
export main;
You can import it with an alias.
import { main as mainOne } from "./file1.js"
import { main as mainTwo } from "./file2.js"
// Call functions
mainOne();
mainTwo();
Or if you export it as default (you can only have one default export per file)
export default main
Then you can import it as whatever
import NewName from "./file1.js"
For more information and examples check the documentation for export here and for import here .
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