How do I solve simple system of equation like the following in python?
x = (2/3)*y + (1/3)*0
y = (2/3)*1 + (1/3)*x
I tried SymPy but couldn't figure it out.
solved the equation part
from sympy import *
from sympy.solvers.solveset import linsolve
x, y = symbols('x, y')
linsolve([x - 2/3*y, y - 2/3 - 1/3*x ], (x, y))
Output: {(0.571428571428571, 0.857142857142857)}
Type is 'sympy.sets.sets.FiniteSet'
How do I extract just the x value to set as a variable?
Got it.
z = linsolve([x - 2/3*y, y - 2/3 - 1/3*x ], (x, y))
print(z.args[0][0])
Using numpy python module
Example solving following system of linear equation
Case 1:
24a + 4b = 35
8a + 4b = 94
Case 2:
a + b = 4
2a + b = 8
>>> import numpy as np
>>> a = np.array([[24, 4],[8,4]])
>>> b = np.array([35, 94])
>>> print(np.linalg.solve(a,b))
[-3.6875 30.875 ]
>>> a = np.array([[1, 1],[2,1]])
>>> b = np.array([4, 8])
>>> print(np.linalg.solve(a,b))
[4. 0.]
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