I have an input nested dict as follows:
{'name': 'Mark', 'marks':[{'english':20, 'maths':25},{'english':50, 'maths':55}]}
The output i am expecting is as follows:
[{'name': 'Mark', 'english':23, 'maths':35}, {{'name': 'Mark', 'english':50, 'maths':55}]
My code is as follows:
In [22]: input = {'name': 'Mark', 'marks':[{'english':20, 'maths':25},{'english':50, 'maths':55}]}
In [23]: marks = input.pop('marks')
In [24]: output = []
In [25]: for mark in marks:
...: output.append({**input, **mark})
...:
In [26]: output
Out[26]:
[{'english': 20, 'maths': 25, 'name': 'Mark'},
{'english': 50, 'maths': 55, 'name': 'Mark'}]
Works as expected.However, this works only for python 3.5 and above since {**x, **y} to merge 2 dicts was only introduced from that version on.
Also my dataset is huge and I am not sure if this is the most efficient way to achieve this.What is the is best way to achieve this python 2.7. I am also open to using external libraries like Pandas
and numpy
.
Here's solution using pandas
:
import pandas as pd
x = {'name': 'Mark', 'marks':[{'english':20, 'maths':25},{'english':50, 'maths':55}]}
x = pd.DataFrame(x)
x = pd.concat([x['name'],x['marks'].apply(pd.Series)], axis=1)
print(x.to_dict(orient='records'))
Output:
[{'english': 20, 'name': 'Mark', 'maths': 25},
{'english': 50, 'name': 'Mark', 'maths': 55}]
PS: tested on python3 but it should work on python2.7 as well
Edit
More generic solution with additional key Now you don't have to hardcode the other keys.
x = {'name': 'Mark', 'add':'Mum','marks':[{'english':20, 'maths':25},{'english':50, 'maths':55}]}
x = pd.DataFrame(x)
cols = list(x.columns)
cols.remove('marks') # to get columns except `mark`
x = pd.concat([x[cols],x['marks'].apply(pd.Series)], axis=1)
print(x.to_dict(orient='records'))
Maybe simple list comprehension though with dirty hack to return the result:
input = {'name': 'Mark', 'marks':[{'english':20, 'maths':25},{'english':50, 'maths':55}]}
marks_list = input.pop('marks')
output = [marks.update(input) or marks for marks in marks_list]
[{'name': 'Mark', 'maths': 25, 'english': 20}, {'name': 'Mark', 'maths': 55, 'english': 50}]
I would use pydash ( https://pydash.readthedocs.io/en/latest/ ), it supports python 2.7:
from pydash import py_ as _
inputs = {'name': 'Mark', 'marks':[{'english':20, 'maths':25},{'english':50, 'maths':55}]}
def construct_dict(d1, d2):
d1.update(d2)
return d1
_(inputs['marks']).map(lambda x: construct_dict({ 'name': inputs['name'] }, x)).value()
# output
[{'maths': 25, 'name': 'Mark', 'english': 20}, {'maths': 55, 'name': 'Mark', 'english': 50}]
in python2.7 i would do the following:
input = {'name': 'Mark', 'marks':[{'english':20, 'maths':25},{'english':50, 'maths':55}]}
marks = input.pop('marks')
output = map(lambda x:dict(input, **x), marks)
With python 2.7:
idict = {'name': 'Mark', 'marks':[{'english':20, 'maths':25},{'english':50, 'maths':55}]}
print (idict)
marks = idict.pop("marks")
result = []
for each in marks:
result.append({'name': idict['name']})
for key, val in each.items():
result[-1][key] = val
print (result)
{'name': 'Mark', 'marks': [{'maths': 25, 'english': 20}, {'maths': 55, 'english': 50}]}
[{'maths': 25, 'name': 'Mark', 'english': 20}, {'maths': 55, 'name': 'Mark', 'english': 50}]
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