a=[1,2,3]
try:
print(a[6])
except IndexError:
print(a[7])
except IndexError:
print(a[1])
Traceback (most recent call last):
File "", line 2, in
IndexError: list index out of range
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "", line 4, in
IndexError: list index out of range
so, I have to use a not graceful way:
a=[1,2,3]
try:
print(a[6])
except IndexError:
try:
print(a[7])
except IndexError:
print(a[1])
Is there any good approach to write the code?
Use can wrap your try: ... except:...
with for loop:
a = [1,2,3]
for i in [6,7,1]:
try:
print(a[i])
except IndexError:
pass
# 2
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.