I am trying to make regex (Django URL) work with with the queryset. I tried different patterns with template URL but it didn't work.
Generic ListView:
class ProductListView(ListView):
template_name = "main/product_list.html"
paginate_by = 4
def get_queryset(self):
tag = self.kwargs["tag"]
self.tag = None
if tag != "all":
self.tag = get_object_or_404(
models.ProductTag, slug=tag
)
if self.tag:
products = models.Product.objects.active().filter(
tags=self.tag
)
else:
products = models.Product.objects.active()
return products.order_by("name")
My URL:
path("products/<slug:tag>/", views.ProductListView.as_view(), name='products'),
Template:
I couldn't get it work in tempalte like below. I tried passing different keyword arguments but it is not working:
<li class="nav-item">
<a class="nav-link" href="{% url 'products' %}">Products</a>
</li>
Error:
Reverse for 'products' with arguments '('',)' not found. 1 pattern(s) tried: ['products\\/(?P<tag>[-a-zA-Z0-9_]+)\\/$']
Your products
route expects a slug argument. So you have to give it one.
It has to be something like
<li class="nav-item">
<a class="nav-link" href="{% url 'products' 'my-nice-slug' %}">Products</a>
</li>
In this case my-nice-slug
should of course be some existing slug.
The previous answer is correct, the exact url you want is simply -
{% url 'products' product.slug %}
if the product
has a slug
field in its model which contains the slug or -
{% url 'products' product.tag %}
if the product
has a tag
field in its model which contains the slug.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.