year_born = input('what year were you born? ')
year = (2019)
age = (year - int(year_born))
if age <= 18:
if age <= 65:
print('Here is your pensioners ticket.')
print('Here is your child's fare ticket.')
else:
print('here is your ticket.')
I tried and elif statement on "if age <= 65:" but it shows syntax error. this works in my last code bellow. so i'm not for sure what is wrong or what I could do to make this work correctly. the problem with this is it does not initiate the "print('Here is your pensioners ticket.')". thanks for the help love you all.
first_name = input('first name only: ')
if len(first_name) >= 5:
if first_name[-1] == 'a':
print('you won $1000!!')
else:
print('you did not win $1000')
else:
print('you did not win $1000')
The error is likely at print('Here is your child's fare ticket.')
because you use '
without escaping it. Possible solutions:
print('Here is your child\'s fare ticket.')
Or
print("Here is your child's fare ticket.")
The way I would approach it:
year_born = input('what year were you born? ')
year = 2019
age = (year - int(year_born))
if age <= 18:
print('Here is your child\'s fare ticket.')
elif age >= 65:
print('Here is your old person ticket.')
else:
print('here is your general adult ticket.')
From a logic standpoint you want prisoners to be 65+ and children are 18 and below. Otherwise they get a regular ticket. If this is correct then I would use the following:
year_born = int(input('what year were you born? '))
year = 2019
age = year - year_born
if age >= 65:
print('Here is your pensioners ticket.')
elif age <= 18:
print('Here is your child\'s fare ticket.') #need to escape the backslash here btw
else:
print('here is your ticket.')
As for the other code you want to check the last letter first, then see if the length is above 5:
first_name = input('first name only: ')
if first_name[-1] == 'a':
print('you won $1000!!')
else:
print('you did not win $1000')
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