I'm trying to create a PHP form where I can add values to a table in my database and this is my code:
<?php
$host ="localhost";
$db_nome = "my_farneseluca";
$username = "farneseluca";
// Create connection
mysql_connect($host, $username) or die('Impossibile connettersi al server: ' . mysql_error());
mysql_select_db($db_nome) or die ('Accesso al database non riuscito: ' . mysql_error());
$table = $_POST['table'];
$descr = $_POST['descr'];
$certif = $_POST['certif'];
$sql = "INSERT INTO $table (DESCRIZIONE, CERTIFICAZIONE) VALUES ('$descr', '$certif');";
if ($con->query($sql) === TRUE)
{
echo 'users entry saved successfully';
}
else
{
echo 'Error: '. $con->error;
}
mysqli_close($con);
?>
<form method="post" action="editdata.php" target="">
Inserire tabella da modificare<br>
<input type="text" name="table"><br>
DESCRIZIONE<br>
<input type="text" name="descr"><br>
CERTIFICAZIONE<br>
<input type="text" name="certif"><br>
<input type="submit" value="Aggiorna">
</form>
When I click the "Aggiorna" button, the page gives this error:
Fatal error: Call to a member function query() on null in /membri/farneseluca/editdata.php on line 96
I tried to see in other posts or in google but i can understand what's the problem
You tried to call query() on $con, but you haven't declared $con anywhere.
Fatal error: Call to a member function query() on null
Define $con:
$con = mysqli_connect($host, $username) or die('Impossibile connettersi al server: ' . mysqli_error());
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