I Have a linked-list of n nodes and each nodes holds more than one element. I am trying to write a method that allows me to search for a node and another method that allows me to search for an element inside the node. I cant figure out how am I suppose to access the inside elements of the nodes of linked list. So I guess what I really want to know is that how do you refer/access each individual element with a node of a linked-list?
Trying to create a program that allows the creation of a linked-list where the number of nodes within that linked-list is user dependent. The list should allow searching for nodes and elements and should also be sorted.
package nodelist;
public class NodeList {
public int nodeid;
public int nodestate;
public int x_cord;
public int y_cord;
public int direction;
public NodeList next;
public NodeList(int nodeid, int nodestate, int x_cord, int y_cord, int direction){
this.nodeid = nodeid;
this.nodestate = nodestate;
this.x_cord = x_cord;
this.y_cord = y_cord;
this.direction = direction;
}
public void display(){
System.out.println("nodeid: "+nodeid + " state: " +nodestate+ " x: " +x_cord+ " y: " +y_cord+ " direction: " +direction);
}
//@Override
public String toString(){
return String.valueOf(this.nodeid); // Needed to convert int nodeid to string for printing
}
public static void main(String[] args) {
// TODO code application logic here
LinkList theLinkedList = new LinkList();
// Insert Link and add a reference to the book Link added just prior
// to the field next
System.out.println("Enter the number of nodes to deploy");
int nodecount = 5;
int nodeid = 5000;
for(int i=0; i<nodecount;i++){
theLinkedList.insertFirstLink(nodeid, 0,0,0,0);
nodeid++;
}
/*
theLinkedList.insertFirstLink("5000", 0,0,0,0);
theLinkedList.insertFirstLink("5001", 1,1,1,1);
theLinkedList.insertFirstLink("5002", 2,2,2,2);
theLinkedList.insertFirstLink("5003", 3,3,3,3);
*/
theLinkedList.display();
System.out.println("Value of first in LinkedList " + theLinkedList.firstLink + "\n");
// Removes the last Link entered
theLinkedList.removeFirst();
theLinkedList.display();
//System.out.println(theLinkedList.find("The Lord of the Rings").bookName + " Was Found");
//theLinkedList.removeNodeList("A Tale of Two Cities");
System.out.println("\nA Tale of Two Cities Removed\n");
theLinkedList.display();
}
}
public class LinkList {
// Reference to first Link in list
// The last Link added to the LinkedList
public NodeList firstLink;
LinkList(){
// Here to show the first Link always starts as null
firstLink = null;
}
// Returns true if LinkList is empty
public boolean isEmpty(){
return(firstLink == null);
}
public void insertFirstLink(int nodeid, int nodestate, int x_cord, int y_cord, int direction){
NodeList newLink = new NodeList(nodeid, nodestate, x_cord, y_cord, direction);
// Connects the firstLink field to the new Link
newLink.next = firstLink;
firstLink = newLink;
}
public NodeList removeFirst(){
NodeList linkReference = firstLink;
if(!isEmpty()){
// Removes the Link from the List
firstLink = firstLink.next;
} else {
System.out.println("Empty LinkedList");
}
return linkReference;
}
public NodeList removeNodeList(){
NodeList linkReference = firstLink;
if(!isEmpty()){
// Removes the Link from the List
firstLink = firstLink.next;
} else {
System.out.println("Empty LinkedList");
}
return linkReference;
}
public void display(){
NodeList theLink = firstLink;
// Start at the reference stored in firstLink and
// keep getting the references stored in next for
// every Link until next returns null
while(theLink != null){
theLink.display();
System.out.println("Next Link: " + theLink.next);
theLink = theLink.next;
System.out.println();
}
}
}
You can only do this if you have same number of element in list of a node. As single node use struct which is declared only once so it's memory has been already decided. So you can't increase the size of node at run-time. Below i have mentioned C++ code.
struct Node{
int list[5];
Node *node;
}
Simply you can do this. Point temp node to head node and then Iterate temp.
System.out.println(temp.your_element_name);
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