How to iterate through *T funcs from struct over reflect.TypeOf(interface{})?

Question

I'm having a few problems iterating through *T funcs from a struct using reflect .

I've searched a lot of answers but none seems to talk specifically about this situation.

I've found a reflect.NewAt at golang documentation but to be honest I didn't understand, and again I couldn't find a single answer for my situation.

For a better understanding... by having the following struct:

type Counter struct {}
func (self *Counter) Add(n int) {}

If I use reflect by calling the struct pointer itself, it works as expected:

y := reflect.TypeOf(&Counter{})

for k := 0; k < y.NumMethod(); k++ {
    fmt.Println(y.Method(k)) // {Add  func(*Counter, int) <func(*Counter, int) Value> 0}
}

But in my case, multiple structs can arrive here, so it arrives as an interface:

var p interface{} = Counter{}

z := reflect.New(reflect.TypeOf(p))

for k := 0; k < z.NumMethod(); k++ {
   fmt.Println(z.Method(k)) // 0x47d150
}

But as shown, it prints the memory address.

I expect the 0x47d150 to be the same output as I was using the pointer directly. What I'm doing wrong here?

Answer 1

The value y a reflect.Type . The Method method on a type is the equivalent of a method expression .

The value z is a reflect.Value . The Method method on a value is the equivalent of a method value .

The printed representation is different because method expressions and method values are not the same thing.

Use reflect.PtrTo to get pointer type for a type:

var p interface{} = Counter{}
z := reflect.PtrTo(reflect.TypeOf(p))
for k := 0; k < z.NumMethod(); k++ {
    fmt.Println(z.Method(k))  // {Add  func(*Counter, int) <func(*Counter, int) Value> 0}
}

The concrete value in the interface is a non-pointer value. You can use this code if the concrete value in the interface is the pointer type:

var p interface{} = &Counter{}
z := reflect.TypeOf(p)
for k := 0; k < z.NumMethod(); k++ {
    fmt.Println(z.Method(k)) // {Add  func(*Counter, int) <func(*Counter, int) Value> 0}
}