How can I delete repetitions in an array without using another array?
Question
How can I delete repetitions in an array without using another array? for example if I write Monday, Wednesday, Monday, Wednesday (in italian: lunedì,mercoledì,lunedì,mercoledi) I need to create a table only with a Monday and a Wednesday
I was thinking of using an if with boolean
ps a switch case match one color to each day of the week
my code
body { color: purple; } table, th, td { border: 1px solid black; width: 44px; } #yellow { background-color: yellow; } #green { background-color: green; } #orange { background-color: orange; } #blue { background-color: blue; } #red { background-color: red; } #purple { background-color: yellowgreen; } #royalblue { background-color: royalblue; }
<!DOCTYPE html> <html> <head> <meta charset="utf-8"> <meta http-equiv="X-UA-Compatible" content="IE=edge"> <title>Giorni colorati</title> <meta name="viewport" content="width=device-width, initial-scale=1"> <link rel="stylesheet" type="text/css" media="screen" href="giornicolorihtml.css"> <script src="main.js"></script> </head> <body> <h1> Tabella giorni con colori </h1> <form action="giornicolorihtml.php"> <label> Scrivi 7 giorni della settimana: <input type="text" name="giorni" value=""> </label> <br> <br> <br> <br> </form> <?php $frase = $_GET['giorni']; $frasespazi=trim($frase); ?> <table> <tr> <?php $arrayfrase = explode (",", $frase); for ($l=0; $l<count($arrayfrase); $l++) { $confronto = $arrayfrase[$l]; for ($i=count($arrayfrase)-1; $i>0; $i--) { if ($confronto != $arrayfrase[$i]) { switch (true) { case ($arrayfrase[$i] == "lunedì"): $varcolor = "yellow"; break; case ($arrayfrase[$i] == "martedì"): $varcolor = "green"; break; case ($arrayfrase[$i] == "mercoledì"): $varcolor = "orange"; break; case ($arrayfrase[$i] == "giovedì"): $varcolor = "blue"; break; case ($arrayfrase[$i] == "venerdì"): $varcolor = "red"; break; case ($arrayfrase[$i] == "sabato"): $varcolor = "purple"; break; case ($arrayfrase[$i] == "domenica"): $varcolor = "royalblue"; break; } } } ?> <td id="<?php echo $varcolor; ?>"> <?php echo $arrayfrase[$l] ."<br>"; } // for esterno ?> </td> </tr> </table> </body> </html>
2 answers
solution1
1 2019-03-30 11:16:41
$array = array("Monday", "Wednesday", "Monday", "Wednesday");
$array = array_unique($array); // Array is now ("Monday", "Wednesday")
I Hope this works
solution2
0 2019-03-30 11:20:51
You could swap the duplicate with the last element in the array, and subtract 1 from its effective length. if you swap, you don't update the current counter, but you subtract 1 from your "final" index. If you don't swap, you update the current counter. Once your current pointer is greater than final, you're done, and the elements past final are the duplicate.
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