So, I have a data.frame with a column called Date.birth, but I have these values in a numeric format:
Date.birth
43067
43060
Probably is problem format. But I need in a Date format like these:
Date.birth
11/28/17
11/21/17
Actually the above format is the correct. I tried this command:
as.Date(levels(data$Date.birth), format="%d.%m.%Y")
but didn't work. Anyone has a suggestion?
Thanks.
We need to specify the origin if it is a numeric
value
as.Date(data$Date.birth, origin = "1899-12-30")
eg
as.Date(43067, origin = "1899-12-30")
#[1] "2017-11-28"
After converting to Date
class, if it needs to be in a custom format, use format
format(as.Date(43067, origin = "1899-12-30"), "%m/%d/%y")
#[1] "11/28/17"
If your column is factor, do convert to numeric first
as.Date(as.numeric(as.character(data$Date.birth)), origin = "1899-12-30")
If this is an excel numeric date, janitor
has a great solution:
library(janitor)
excel_numeric_to_date(data$Date.birth)
It can be simply done by using lubridate
package-
lubridate::as_date(as.numeric(dt$Date.birth),origin="1899-12-30")
[1] "2017-11-28" "2017-11-21"
Sample Data-
dt <- read.table(text="Date.birth
43067
43060",header=T)
try this
VariableName <- dt %>%
mutate(Date.birth = format(excel_numeric_to_date(as.numeric(Date.birth)),"%m/%d/%y"))
#[1] "11/28/17"
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