Filter items into the array within the array?

Question

 const personData = { personList: [ { personCodes: [ { code: "001", desc: "Indian" } ] }, { personCodes: [ { code: "002", desc: "Spanish" } ] }, { personCodes: [ { code: "001", desc: "Spanish" }, { code: "002", desc: "Spanish1" }, { code: "003", desc: "Spanish2" } ] }, { personCodes: [ { code: "001", desc: "Russian" } ] }, { personCodes: [ { code: "001", desc: "Spanish" }, { code: "002", desc: "Indian" }, { code: "004", desc: "Japanina" } ] }, { personCodes: [ { code: "001", desc: "Spanish" }, { code: "004", desc: "Indian" }, { code: "003", desc: "Japanina" } ] }, ] }; const personID = ["001","003"]; const result = personData.personList.filter(role => role.personCodes && role.personCodes.find(group => personID.includes(group.code))); console.log(result);

Following code denotes the person Data with person List. Each person List represents the code. Once executing the code I am getting the 5 different kind of array which contains the code into the personID array. I want the expected out like from the person Data 3rd and 6th object. could someone look into it and modified the code ,I have already attached the required code. Thanks

Answer 1

You can use every() on personID and then use find() inside that.

 const personData = { personList: [ { personCodes: [ { code: "001", desc: "Indian" } ] }, { personCodes: [ { code: "002", desc: "Spanish" } ] }, { personCodes: [ { code: "001", desc: "Spanish" }, { code: "002", desc: "Spanish1" }, { code: "003", desc: "Spanish2" } ] }, { personCodes: [ { code: "001", desc: "Russian" } ] }, { personCodes: [ { code: "001", desc: "Spanish" }, { code: "002", desc: "Indian" }, { code: "004", desc: "Japanina" } ] }, { personCodes: [ { code: "001", desc: "Spanish" }, { code: "004", desc: "Indian" }, { code: "003", desc: "Japanina" } ] }, ] }; const personID = ["001","003"]; const result = personData.personList.filter(role => role.personCodes && personID.every(x => role.personCodes.find(a => x.includes(a.code)) )); console.log(result);

Answer 2

Here you have another solution, basically you have to check with Array.every() and Array.some() if for every element id inside personID some object inside a personCodes array have a property code that equals id .

 const personData = { personList: [ { personCodes: [ { code: "001", desc: "Indian" } ] }, { personCodes: [ { code: "002", desc: "Spanish" } ] }, { personCodes: [ { code: "001", desc: "Spanish" }, { code: "002", desc: "Spanish1" }, { code: "003", desc: "Spanish2" } ] }, { personCodes: [ { code: "001", desc: "Russian" } ] }, { personCodes: [ { code: "001", desc: "Spanish" }, { code: "002", desc: "Indian" }, { code: "004", desc: "Japanina" } ] }, { personCodes: [ { code: "001", desc: "Spanish" }, { code: "004", desc: "Indian" }, { code: "003", desc: "Japanina" } ] }, ] }; const personID = ["001", "003"]; const result = personData.personList.filter(role => { return Array.isArray(role.personCodes) && personID.every(id => role.personCodes.some(p => p.code === id)); }); console.log(result);

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