PHP mysqli_fetch_all to get total rows and data together

Question

I used to working on Oracle DB with PHP.

$strSQL = oci_parse($c1, "SELECT * FROM tb_users");
oci_execute($strSQL);
$Num_Rows = oci_fetch_all($strSQL, $dData);

That above code is working OK. I can get total rows and show the data using variable $dData[]

And now I'm using mySQL DB with PHP.

$strSQL = mysqli_query($c1, "SELECT * FROM tb_users");
$Num_Rows = mysqli_fetch_all($strSQL, $dData);

When I try to run the code (mySQL), the value of $Num_Rows is empty (I'm sure there is an data on db). And the data is not show using $dData .

My question, is mysqli_fetch_all correct? Or is there another way?

Answer 1

$strSQL = mysqli_query($c1, "SELECT * FROM tb_users");
$Num_Rows = mysqli_fetch_all($strSQL, $dData);

if you use loop then it will give result for individual record

while($Num_Rows = mysqli_fetch_all($strSQL, $dData)){
print_r($Num_Rows);
}

if you want number of rows then just

$num_rows=count($Num_Rows)

OR Use

mysqli_num_rows