I have a list like this:
[{'FirstOfficer': '1'}, {'SecondOfficer': '2'}, {'ThirdOfficer': '3'},{'FirstOfficer': '4'}, {'SecondOfficer': '5'}, {'ThirdOfficer': '6'},{'FirstOfficer': '7'}, {'SecondOfficer': '8'}, {'ThirdOfficer': '9'},{'FirstOfficer': '10'}, {'SecondOfficer': '11'}, {'ThirdOfficer': '12'}]
I wanted to convert this into a dataframe but i got the dataframe like this:
FirstOfficer SecondOfficer ThirdOfficer
0 1 NaN NaN
1 NaN 2 NaN
2 NaN NaN 3
3 4 NaN NaN
4 NaN 5 NaN
5 NaN NaN 6
6 7 NaN NaN
7 NaN 8 NaN
8 NaN NaN 9
9 10 NaN NaN
10 NaN 11 NaN
11 NaN NaN 12
the columns name can be anything, so I am not able to hard code it.
Expected dataframe is:
FirstOfficer SecondOfficer ThirdOfficer
0 1 2 3
1 4 5 6
2 7 8 9
3 10 11 12
Can anybody suggest me a solution for it?
Any help would be appreciated.
Use defaultdict
for store values to list by keys of dictionaries:
from collections import defaultdict
d = defaultdict(list)
for x in L:
a, b = tuple(x.items())[0]
d[a].append(b)
print (d)
df = pd.DataFrame(d)
print (df)
FirstOfficer SecondOfficer ThirdOfficer
0 1 2 3
1 4 5 6
2 7 8 9
3 10 11 12
If performance is not an issue, you can use:
df=pd.DataFrame(l).apply(lambda x: pd.Series(x.dropna().values))
print(df)
FirstOfficer SecondOfficer ThirdOfficer
0 1 2 3
1 4 5 6
2 7 8 9
3 10 11 12
d = [{'FirstOfficer': '1'}, {'SecondOfficer': '2'}, {'ThirdOfficer': '3'}, {'FirstOfficer': '4'}, {'SecondOfficer': '5'}, {'ThirdOfficer': '6'}, {'FirstOfficer': '7'}, {'SecondOfficer': '8'}, {'ThirdOfficer': '9'}, {'FirstOfficer': '10'}, {'SecondOfficer': '11'}, {'ThirdOfficer': '12'}]
keys = list(set([str(i.keys()).split("'")[1] for i in d]))
final_dict = dict()
for key in keys:
final_dict['key'] = [i[key] for i in d if key in i.keys()]
df = pd.DataFrame.from_dict(final_dict)
OUTPUT:
FirstOfficer SecondOfficer ThirdOfficer
0 1 2 3
1 4 5 6
2 7 8 9
3 10 11 12
One approach is to pre-process your list
Ex:
import pandas as pd
lst = [{'FirstOfficer': '1'}, {'SecondOfficer': '2'}, {'ThirdOfficer': '3'},{'FirstOfficer': '4'}, {'SecondOfficer': '5'}, {'ThirdOfficer': '6'},{'FirstOfficer': '7'}, {'SecondOfficer': '8'}, {'ThirdOfficer': '9'},{'FirstOfficer': '10'}, {'SecondOfficer': '11'}, {'ThirdOfficer': '12'}]
data = []
for i in range(0, len(lst), 3):
temp = []
for d in lst[i:i+3]:
for _, v in d.items():
temp.append(v)
data.append(temp)
df = pd.DataFrame(data, columns=["FirstOfficer", "SecondOfficer", "ThirdOfficer"])
print(df)
Output:
FirstOfficer SecondOfficer ThirdOfficer
0 1 2 3
1 4 5 6
2 7 8 9
3 10 11 12
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