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How to scrape images from DuckDuckGo's image search results in Python

I'm creating an application with python that's going to show images scraped from DuckDuckGo's image search results. So I need to get a list of links to the images based on the search. The problem is that the HTML that constitutes DuckDuckGo's image search results does not contain any image tags but instead, the images seem to be stored in division tags. How can I with the help of python scrape those damn links to the images and store them in a variable on my program?

What I want my variable to look like:

image_links = ["https://duckduckgo.com/?q=duckduckgo&atb=v166-4_p&iax=images&ia=images&iai=https%3A%2F%2Fupload.wikimedia.org%2Fwikipedia%2Fen%2Fthumb%2F8%2F88%2FDuckDuckGo_logo.svg%2F1200px-DuckDuckGo_logo.svg.png","https://duckduckgo.com/?q=duckduckgo&atb=v166-4_p&iax=images&ia=images&iai=https%3A%2F%2Fupload.wikimedia.org%2Fwikipedia%2Fen%2Fthumb%2F8%2F88%2FDuckDuckGo_logo.svg%2F1200px-DuckDuckGo_logo.svg.png"]

A visualization of DuckDuckGo's HTML structure in its image search results

Edit:

When I scrape the HTML from the URL by doing this:

source = urllib.request.urlopen("https://duckduckgo.com/?q=duckduckgo&atb=v166-4_p&iax=images&ia=images").read()

it doesn't return any image tags at all.

I am checking that by doing this:

source_tree = BeautifulSoup(source, 'html.parser')

links = [img.get('src') for img in source_tree.find_all('img', _class='tile--img__img')]

print(f"links: {links}")
print(f"img in source_tree: {'img' in str(source_tree)}")
print(f"source_tree: {source_tree}")

Output:

links: []
img in source_tree: False
source_tree: <!DOCTYPE html>
<html class="no-js has-zcm" lang="en_US"><head><meta content="text/html; charset=utf-8" http-equiv="content-type"/><title>duckduckgo at DuckDuckGo</title><link href="/s1775.css" rel="stylesheet" type="text/css"/><link href="/r1775.css" rel="stylesheet" type="text/css"/><meta content="noindex,nofollow" name="robots"/><meta content="origin" name="referrer"/><meta content="duckduckgo" name="apple-mobile-web-app-title"/><link href="/favicon.ico" rel="shortcut icon" sizes="16x16 24x24 32x32 64x64" type="image/x-icon"><link href="/assets/icons/meta/DDG-iOS-icon_60x60.png?v=2" id="icon60" rel="apple-touch-icon"><link href="/assets/icons/meta/DDG-iOS-icon_76x76.png?v=2" id="icon76" rel="apple-touch-icon" sizes="76x76"/><link href="/assets/icons/meta/DDG-iOS-icon_120x120.png?v=2" id="icon120" rel="apple-touch-icon" sizes="120x120"/><link href="/assets/icons/meta/DDG-iOS-icon_152x152.png?v=2" id="icon152" rel="apple-touch-icon" sizes="152x152"/><link href="/assets/icons/meta/DDG-icon_256x256.png" rel="image_src"/><script type="text/javascript">var ct,fd,fq,it,iqa,iqm,iqs,iqp,iqq,qw,dl,ra,rv,rad,r1hc,r1c,r2c,r3c,rfq,rq,rds,rs,rt,rl,y,y1,ti,tig,iqd,locale,settings_js_version='s2472.js',is_twitter='',rpl=0;fq=0;fd=1;it=0;iqa=0;iqbi=0;iqm=0;iqs=0;iqp=0;iqq=0;qw=1;dl='';ct='DK';iqd=0;r1hc=0;r1c=0;r3c=0;rq='duckduckgo';rqd="duckduckgo";rfq=0;rt='A';ra='';rv='';rad='';rds=30;rs=0;spice_version='1396';spice_paths='{}';locale='en_US';settings_url_params={};rl='wt-wt';rlo=0;df='';ds='';sfq='';iar='';vqd='3-146459744347044482638673072010848595657-89706121844226791728716680155105882500';safe_ddg=0;;</script><meta content="width=device-width, initial-scale=1" name="viewport"><meta content="true" name="HandheldFriendly"><meta content="no" name="apple-mobile-web-app-capable"/></meta></meta></link></link></head><body class="body--serp"><input id="state_hidden" name="state_hidden" size="1" type="text"/><span class="hide">Ignore this box 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[Finished in 0.6s]

What's the reason for this and how can I fix it?

The images are actually stored in img tags, they are just nested inside of some div elements.

DuckDuckGo 图片搜索 IMG 标签

You should be able to find all of the images on the page with the CSS selector img.tile--img__img .

You could use a library like Beautiful Soup to query for all of those links, like so:

from bs4 import BeautifulSoup

# Considering your HTML is in the variable `source`
source_tree = BeautifulSoup(source, 'html.parser')

links = [img.get('src') for img in source_tree.find_all('img', class_='tile--img__img')]

Edit

Seems like the issue here is that duckduckgo serves the images page with the use of some JavaScript to display all of the img tiles. Since the Python request can only fetch the resources and not execute any JavaScript, then you may need to implement a different solution. See this other SO answer for some options.

As duckduckgo doesn't provide any api for image search but it does fetch the image using a request call.
So I have got this another solution which may work. Here this solution will only work for a keyword = book . Because image search request is using a parameter vqd which is dynamic eiter on the basis of searched keyword or the user's machine.
If that can be solved this code will work for any keyword to download any image.

If anyone can decrypt this vqd, just replace :

'q': 'book',

with

'q': keyword,

and the rest is fine.

from bs4 import *
import requests as rq
import os

# api-endpoint
URL = "https://duckduckgo.com/i.js"
keyword = input('Enter the search keyword : ')

# defining a params dict for the parameters to be sent to the API
PARAMS = {'l': 'us-en',
    'o': 'json',
    'q': 'book',
    'vqd': '3-160127109499719016074744569811997028386-179481262599639828155814625357171050706&f=,,,',
}

# sending get request and saving the response as response object
r = rq.get(url=URL, params=PARAMS)

# extracting data in json format
data = r.json()

img_link = data["results"][0]['image']

img_data = rq.get(img_link).content

# os.mkdir('downloads')
filename = "downloads/" + keyword + ".png"
with open(filename, 'wb+') as f:
    f.write(img_data)

print("File " + keyword + ".png successfully downloaded.")

If this helped you let me know by thumbs up this answer.
If anyone have any solution / update do let us know also.

========================= Updated Answer =========================

There is a github package available for this also. The main problem with the above script was the value of that parameter (vqd). With the help of this package I have created the following script.

import requests
import re
import json
import os


def search(keywords, max_results=None):
    url = 'https://duckduckgo.com/'
    params = {
        'q': keywords
    }

    print("Hitting DuckDuckGo for Token")

    #   First make a request to above URL, and parse out the 'vqd'
    #   This is a special token, which should be used in the subsequent request
    res = requests.post(url, data=params)
    searchObj = re.search(r'vqd=([\d-]+)\&', res.text, re.M | re.I)

    if not searchObj:
        print("Token Parsing Failed !")
        return -1

    print("Obtained Token")

    headers = {
        'dnt': '1',
        'accept-encoding': 'gzip, deflate, sdch, br',
        'x-requested-with': 'XMLHttpRequest',
        'accept-language': 'en-GB,en-US;q=0.8,en;q=0.6,ms;q=0.4',
        'user-agent': 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/55.0.2883.87 Safari/537.36',
        'accept': 'application/json, text/javascript, */*; q=0.01',
        'referer': 'https://duckduckgo.com/',
        'authority': 'duckduckgo.com',
    }

    params = (
        ('l', 'wt-wt'),
        ('o', 'json'),
        ('q', keywords),
        ('vqd', searchObj.group(1)),
        ('f', ',,,'),
        ('p', '2')
    )

    requestUrl = url + "i.js"

    try:
        res = requests.get(requestUrl, headers=headers, params=params)
        data = json.loads(res.text)
        saveImage(data["results"], keywords)
    except ValueError as e:
        print('Please try later.')

    # logger.debug("Hitting Url Success : %s", requestUrl)


def saveImage(objs, keyword):
    for obj in objs:
        img_link = obj['image']
        img_data = requests.get(img_link).content

        # os.mkdir('downloads')
        filename = "downloads/" + keyword + ".png"
        with open(filename, 'wb+') as f:
            f.write(img_data)

        print("File " + keyword + ".png successfully downloaded.")
        break


while True:
    keyword = input('Enter the search keyword : ')
    # print(keyword)
    search(keyword)

My solution was using selenium as proposed in the answer marked as right.

from urllib.parse import unquote 
from selenium import webdriver

def search(query):
    driver = webdriver.Firefox()

    # For one word queries it will be ok, for complex ones should encode first
    driver.get(f'https://duckduckgo.com/?q={query}&t=h_&iax=images&ia=images') 

    # For now it's working with this class, not sure if it will never change
    img_tags = driver.find_elements_by_class_name('tile--img__img') 

    for tag in img_tags:
        src = tag.get_attribute('data-src')
        src = unquote(src)
        src = src.split('=', maxsplit=1)
        src = src[1]
        yield src

    driver.close()

if __name__ == '__main__':
    from pprint import pprint
    imgs_urls = list(search('sun'))
    pprint(imgs_urls)

You'll need selenium python library, that you can install using pip and geckodriver, that may be found in your distribution package manager.

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